What is the equivalent value for NSRange.location on the Range Object within Swift 3?

Question

Did someone can give me a hint which property of a Range is the equivalent property to the location property of an NSRange.

Especially I'm interested how I would migrate the following line of code from Swift 2.3 -> Swift 3.0

if myRange.location != NSNotFound { ... }

myRange is still a Range property and so the compiler tells me correct: Value of Type Range has no member location

Is it enough to check the empty property?

if !myRange.isEmpty { ... }

Thanks in advance

Most functions that used to return a range with `NSNotFound` now return an optional Range instead. So it should be enough to check that the range is not `nil`. — Fogmeister, Jan 06 '17 at 16:26
Good to know! In my case it is a self created range over a Data-Object (previously NSData), therefore the nil check doesn't work. — matzino, Jan 06 '17 at 16:37
If it's a function you've written yourself then change it to return an optional ;-) — Fogmeister, Jan 06 '17 at 16:38

score 3 · Accepted Answer · answered Apr 05 '18 at 04:45

Like the comments say, instead of returning NSNotFound you will get a nil range.

To answer your question though .location has been replaced with .lowerBound and .upperBound.

let s = "The yellow dog is nice"
if let range = s.range(of: "dog")
{
    print(s[range.lowerBound...]) //prints "dog is nice"
    print(s[range.upperBound...]) //prints " is nice"
    print(s[range.lowerBound..<range.upperBound]) //prints "dog"
}

What is the equivalent value for NSRange.location on the Range Object within Swift 3?

1 Answers1