6

I've a sample example below, I'm not sure why the first example (using div's) didn't get the text when the second one (using span's) could achieve that with the same JS code using closest():

$('.class-1').closest('div').find('.class-2').text()

First snippet (using div's) cant get the text using closest(): 

console.log( $('.class-1').closest('div').find('.class-2').text() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
  <div class="class-1">Div 1 Content</div>
  <div class="class-2">Div 2 Content</div>
</div>

Second snippet (using span's) getting the text using closest():

console.log( $('.class-1').closest('div').find('.class-2').text() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
  <span class="class-1">Div 1 Content</span>
  <br/>
  <span class="class-2">Div 2 Content</span>
</div>

I know about the alternatives parents()/parent()/siblings()/nextAll() that can return the class-2 text in this case, but I want just to know what occur this behaviour.

Zakaria Acharki
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    It's because `closest()` includes the current element, therefore `closest('div')` is returning the same element. See http://api.jquery.com/closest – Rory McCrossan Jan 06 '17 at 14:45

1 Answers1

12

Because .closest() checks if the calling element fits the selector as well, and in your case .class-1 is also a div.

From the docs:

Description: For each element in the set, get the first element that matches the selector by testing the element itself and traversing up through its ancestors in the DOM tree.

Ori Drori
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