How can I convert a std::vector to std::vector?

Question

I have found this question a few times, but none of them seem to offer a good answer (please mark as duplicate if I missed it).

I have a method that returns a std::vector<unsigned short>, but I want to allow for more numbers than an unsigned short can hold, so I would like to convert it to a std::vector<int> before I add my bigger numbers to it.

So I want to convert it while keeping the data & order intact. A std::vector<unsigned short> that contains [1, 2, 3] should contain [1, 2, 3] after it has been converted to std::vector<int>.

Why not using range constructor? – Edgar Rokjān Dec 29 '16 at 13:53 — Edgar Rokjān, Dec 29 '16 at 13:53
@EdgarRokyan yes this is what I need. – vrwim Dec 29 '16 at 13:57 — vrwim, Dec 29 '16 at 13:57

score 4 · Answer 1 · answered Dec 29 '16 at 13:54

4

Just construct the std::vector<int> from the std::vector<unsigned short>:

std::vector<unsigned short> org_vec;

// ...

std::vector<int> int_vec(std::begin(org_vec), std::end(org_vec));

answered Dec 29 '16 at 13:54

Paul Evans

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How can I convert a std::vector to std::vector?

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