Instantiating a class does not work, constructor parameter is interface

Question

i tried to create a instance of a class that implemented an interface, but the problem is that the constructor takes a parameter which is the interface itself.

Information: I dont want to implement the interface, class or funcinality by myself, because the library EJML has implemented it already, i just want to use the class and the functions.

    public class myMatrixFactory{
        public void do(){
            //Does not work because LinearSolver_B64_to_D64() needs a interface as parameter
            // parameter is LinearSolver<BlockMatrix64F> which is an interface
            LinearSolver_B64_to_D64 ls = new LinearSolver_B64_to_D64(????);
        }
    }

Did you read the funky manual? http://ejml.org/wiki/index.php?title=Solving_Linear_Systems — , Dec 23 '16 at 12:02
Thank, as i am very new to programming, i am not familiar using the javadoc and manuals. — M.Mac, Dec 23 '16 at 12:28

score 2 · Accepted Answer · answered Dec 23 '16 at 12:01

2

You have to create an object of a class that implements the required interface and pass it to the constructor.

According to the link you provided you need an object of type LinearSolver<BlockMatrix64F> so you should take a look at this classes javadoc and choose one of the implementing classes.

answered Dec 23 '16 at 12:01

JayTheKay

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I would say `LinearSolverFactory` should be used – Dec 23 '16 at 12:03
Helped me alot, also referring to the manual makes everthing clear! – M.Mac Dec 23 '16 at 12:19

Instantiating a class does not work, constructor parameter is interface

1 Answers1