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I just encountered the following situtation:

The test-server is currently running Flyway, with version 1 (V1). The test-server is automatically updated (including Flyway scripts) whenever anything is pushed on the develop branch.

A developer decides to start working on a new feature on branch feature/123. This developer creates a database script (Flyway compatible) called V2__cool_feature.sql. In the meantime, another developer also starts working on a feature branch called feature/456. This developer is also in need of an update script, and names it V3__another_cool_feature.sql, because the developer knows that V2 is already used on another branch. This feature/456 branch is finished and is merged, and so the current scripts on the develop branch are V1 & V3. This works well and the V3 script is executed, leaving Flyway its schema_version on version 3.

The other feature branch feature/123 is also merged, which means that the develop branch contains the scripts V1, V2 & V3.

Now this is were I'm having trouble with Flyway:

The build, including Flyway, is executed and it leaves the following message:

[INFO] Database: jdbc:mysql://example.com:3306/my_schema (MySQL 5.5)
[INFO] Successfully validated 2 migrations (execution time 00:00.019s)
[INFO] Current version of schema `my_schema`: 3
[INFO] Schema `my_schema` is up to date. No migration necessary.

What I want to happen is that the V2 script is executed, and I'm not sure how to do so.

I hope I explained my problem well, if not, please leave a comment.

Jelle den Burger
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1 Answers1

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Ugh, I'm not a smart guy. Putting a bit more effort into my Googling skills lands me upon the Flyway documentation, describing exactly my problem:

Option: outOfOrder

Required: NO

Default: false

Description: Allows migrations to be run "out of order". If you already have versions 1 and 3 applied, and now a version 2 is found, it will be applied too instead of being ignored. (Even the same versioning as in my question is used >.< )

Jelle den Burger
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