class Cell(var x: Int)
var c = new Cell(1)
val f1 = () => c.x /* Create a closure that uses c */
def foo(e: Cell) = () => e.x /* foo is a closure generator with its own scope */
// f2 wont do any reference/deep copy
val f2 = foo(c) /* Create another closure that uses c */
val d = c /* Alias c as d */
c = new Cell(10) /* Let c point to a new object */
d.x = d.x + 1 /* Increase d.x (i.e., the former c.x) */
// now c.x refers to 10
println(f1()) /* Prints 10 */
println(f2()) /* Prints 2 */
Here the f2() prints 2 , As scala wont do deep copy, why the value is still persisted as 1, it should be 10.. where i am going wrong
2) I had read smomehere, Closure in scala dont deep copy the objects, they just keep reference to the object. what do it exactly mean