Converting my php array to equivalent jQuery Array

Question

I have an array in PHP and want to use that data inside my Jquery, I have converted that to json and here is my full code.

$mine = array(
'new' => 'new',
'old' => 'old'
);

and I have converted it like this

$result = json_encode(array_values($cat));

and now I got my results like show below:

[{"new":"new","old":"old"}]

this is wrong one, because I want it to be like this way.

[
{"new":"new"},
{"old":"old"}
]

I don't know where am I doing any thing wrong but I am unable to get this simple thing done ... any one to help me out of this simple question please ... I really have been through many earlier questions like json_encode sparse PHP array as JSON array, not JSON object

But still unable to get this work for me, any one there to help me out pelase ???

Try to use `$result=json_encode($mine)` in php and `$.parseJSON(json)` in jQuery. — Miron, Dec 13 '16 at 13:47
In the comments to an answer you showed your "actual code". Please put it in the question too, since it seems to be pretty different. — Aioros, Dec 13 '16 at 15:42

score 1 · Accepted Answer · answered Dec 13 '16 at 13:52

1

Your array has to look like this in PHP:

$mine = array(
array('new' => 'new'),
array('old' => 'old')
);

json_encode transforms a php array to a json object ( {} )if it is a dictionary (Associative) and transforms it to a json array ( [] ) if it is a list without keys.

answered Dec 13 '16 at 13:52

Iarwa1n

460
3
12

here is my actual code $cat = array(); $categories = $categories = get_categories(array('hide_empty' => true)); //print_r($categories); foreach($categories as $category){ $cat['name'][$category->name] = $category->slug; } – laraib Dec 13 '16 at 13:57
Array ( [0] => Array ( [another] => another ) [1] => Array ( [Uncategorized] => uncategorized ) ) now this is my array in php ... how can i make it like I already shown structure in jquery ? – laraib Dec 13 '16 at 14:01
This looks already right as your key/value pairs are inside extra array. Does json_encode not work correclty with this? – Iarwa1n Dec 13 '16 at 14:51

score 0 · Answer 2 · answered Dec 13 '16 at 13:50

0

You got a bit wrong structure of your php object it should be:

$mine = array(
   array('new' => 'new'),
   array('old' => 'old')
);

Check example.

answered Dec 13 '16 at 13:50

teo van kot

12,350
10
38
70

Array ( [0] => Array ( [another] => another ) [1] => Array ( [Uncategorized] => uncategorized ) ) now this is my array in php ... how can i make it like I already shown structure in jquery ? – laraib Dec 13 '16 at 14:02
the problem is that I am getting that data from ajax success method and then pushing that respone json to my jquery array ... then I want to use that array ... any one who can guide me properly plz ? – laraib Dec 13 '16 at 14:04

score 0 · Answer 3 · answered Dec 13 '16 at 15:13

0

You can also do like this:

var encodedVar=json_encode($array_nm);
var js_array=$.paseJSON(encodedvar);
for(var i=0;i<js_array.length;i++){
    console.log(js_array[i]);//it will display value by index just like php array....
}

answered Dec 13 '16 at 15:13

GhanuBha

142
7

Converting my php array to equivalent jQuery Array

3 Answers3