Showing string with charAt in a do-while loop

Question

index = 0;
string1 = '1,2,3,4,5,6,8,9,0#';
string2 = '1,2,3#';
do{
    document.write(string1.charAt(index));
    index++;
}
while(string1.charAt(index) != '#');
index = 0;
document.write('<br />');
do{
    document.write(string2.charAt(index));
    index++;
}
while(string2.charAt(index) != '#');

Hello there, i am stuck at a Javascript assignment and i need to show the strings above in a do-while loop and i have to use charAt to do so. and i need the loop to stop at the # sign. But the charAt method only showed one number,

so my qeustion is: how can i show all the numbers with charAt? and how can i stop my do-while loop when the # sign is equal to the # sign

Can you show us what have you tried so far? A jsfiddle would be nice too. We arent going to work for you. You will learn nothing if you dont try. — aloisdg, Dec 13 '16 at 08:40
My mind reading powers say you forgot to increment the `index` inside your loop. Or you are not actually using `index` as a parameter for `charAt` — UnholySheep, Dec 13 '16 at 08:42

score 0 · Accepted Answer · answered Dec 13 '16 at 08:51

0

const string = '1,2,3,4,5,6,7,8,9,0#';
let index = 0;

do {
  const char = string.charAt(index);
  if (char !== ',') console.log(char);
  index++;
} while (string.charAt(index) !== '#');

answered Dec 13 '16 at 08:51

GG.

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score 0 · Answer 2 · answered Dec 13 '16 at 09:03

Here is what you want.

index = 0
string1 = '1,2,3,4,5,6,7,8,9,0#'

do {
  if (string1.charAt(index) !== ',') 
    console.log(string1.charAt(index))
  index++
} while (string1.charAt(index) !== '#')

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Showing string with charAt in a do-while loop

2 Answers2