Swift, is it possible to have an IBInspectable block?

Question

I have approximately 50 properties in my view that I must make inspectable.

Is there a way to do so without declaring it explicitly for each one?

score 1 · Accepted Answer · answered Nov 16 '16 at 13:29

1

Unfortunately, no. @IBDesignable and @IBInspectable must be declared explicitly for each class/property you wish to show up in interface builder.

answered Nov 16 '16 at 13:29

Jake

1 Answers1