-4

I have this logical operator expression:

!(!(a != b) && (b > 7))

How do you simplify it and find the equivalent?

OneCricketeer
  • 179,855
  • 19
  • 132
  • 245
mbo
  • 3
  • 3

2 Answers2

2

Use Demorgan's Laws.

!(!(a != b) && (b > 7))
!!(a != b) || !(b > 7)
a != b || b <= 7
pscuderi
  • 1,554
  • 12
  • 14
0

As mentioned by others: Demorgan's Laws

!(!(a != b) && (b > 7)) // x != y --> !(x == y) 
!(!!(a == b) && (b > 7)) // !!x --> x 
!((a == b) && (b > 7)) // !(x && y) --> !x || !y
!(a == b) || !(b > 7) // !(x == y) --> x != y;; !(x > y) --> x <= y
(a != b) || (b <= 7)
MrLowbob
  • 102
  • 6