Integer to char - cast and print:

Question

I want to know the logic behind this programm and (char) cast. How does it work and how it is printing all the letters, symbols and numbers

package ascii1
public class Ascii1 {

    public static void main(String[] args) {
        int i=1;
        while(i<122)
        {
            System.out.println((char)i+"\t");
            if (i%10==0)
                System.out.println("");
            i++;
        }

        } 
}

Its output is:

//Blanks in the beginning...

! "

$ % & ' (

) * + ,
- . / 0 1 2

3 4 5 6 7 8 9 : ; <

=

? @ A B C D E F

G H I J K L M N O P

Q R S T U V W X Y Z

[ \ ] ^
_ ` a b c d

e f g h i j k l m n

o p q r s t u v w x

y BUILD SUCCESSFUL (total time: 0 seconds)

what is your actual question on this code? – Timothy Truckle Nov 06 '16 at 10:15 — Timothy Truckle, Nov 06 '16 at 10:15
This is the most awefully formatted question I have seen. – martijnn2008 Nov 06 '16 at 10:36 — martijnn2008, Nov 06 '16 at 10:36

score 1 · Accepted Answer · answered Nov 06 '16 at 10:15

1

Using ASCII representation, every char has a numerical value.

When you iterate, adding +1 to the i variable, you get to numbers on the ASCII table representing some characters.

Finally, the (char) cast returns the above ASCII character.

answered Nov 06 '16 at 10:15

MordechayS

1,552
2
19
29

1

Unicode characters with values under 32 are the so-called control characters, they don’t have a graphical representation, which is why you see nothing in the first several linesof output. – Ole V.V. Nov 06 '16 at 10:59

Integer to char - cast and print:

$ % & ' (

1 Answers1