Multilevel Inheritance Error "cout does not name a type"

Question

Cout Does not Name a Type

Folks, why I am getting this error even I am using "iostream and using namespace std"

Here is My Code

   class DateType: public PatientType{

    cout<<"\nEnter Patient ID\n";
    cin>>Patient_ID;
    cout<<"\nEnter  Patient's Age\n";
    cin>>Age;
    cout<<"\nEnter Patient's Date of Birth";
    cin>>DOB;
};

Class DateType is Derived from class PatientType and class PatientType is Dervied from Class PersonType.

cout is working everywhere but in class DateType.

You might want to get [a good book on C++](http://stackoverflow.com/q/388242/253056). — Paul R, Nov 03 '16 at 10:11
What are you trying to do? When do you want those lines of code to be run? You will get the same error even without using inheritnce. — doctorlove, Nov 03 '16 at 10:15
My bad, I was assuming that I am writing code in a function but that was in class — Mohiyo Deen, Nov 03 '16 at 10:17

score 3 · Accepted Answer · answered Nov 03 '16 at 10:11

cout<<"\nEnter Patient ID\n"; is a statement that needs to be inside a function.

This, and your other statements, are floating somewhere in the class definition. This is not syntactically valid.

This is confusing the compiler and is issuing a somewhat cryptic error.

score 1 · Answer 2 · answered Nov 03 '16 at 10:11

1

Your code is outside any function, and this is incorrect.

answered Nov 03 '16 at 10:11

Andrea

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Multilevel Inheritance Error "cout does not name a type"

2 Answers2