How to decode json in yii 1

Question

I have following codes in my controller:

public function actionCabinet($id){

    $this->render('cabinet', array('model'=>$this->loadJson($id)) );

}

    public function loadJson($id)
    {

        $jsonfile=ChForms::model()->findByPk($id, array("select"=>"json"));
        $decodedJson=json_decode($jsonfile, true);
        return $decodedJson;

    }

Data is saved in json field in ChForm in json format. I am going to convert it to array. When I run this application, it displays following error message:

json_decode() expects parameter 1 to be string, object given

How can I fix this error?

what's the output of `var_dump($jsonfile);`, is it a valid `JSON`? — Sandip Pingle, Nov 02 '16 at 09:18

score 1 · Accepted Answer · answered Nov 02 '16 at 10:50

1

Please try this,

 public function loadJson($id)
{

    $jsonfile=ChForms::model()->findByPk($id);
    $decodedJson=json_decode($jsonfile->json, true);
    return $decodedJson;

}

answered Nov 02 '16 at 10:50

Arya

504
2
8
31

score -1 · Answer 2 · answered Nov 02 '16 at 09:35

-1

You can use json_encode like below,

public function loadJson($id)
{

    $jsonfile=ChForms::model()->findByPk($id, array("select"=>"json"));
    $decodedJson=json_encode($jsonfile, true);
    return $decodedJson;

}

answered Nov 02 '16 at 09:35

KasunSm

9
2

1

json_encode is used for convert an array to json format. – Arya Nov 03 '16 at 04:07

How to decode json in yii 1

2 Answers2