Search array of object with filter and keyword

Question

I have an array, filter and keyword. i want to search in that array using filter and keyword, with result array of object too. Just like first array.

var data = [
  {email: "usera@gmail.com",nama:"User A", Level:"Super Admin"},
  {email: "userb@gmail.com",nama:"User B", Level:"Super Admin"},
  {email: "userc@gmail.com",nama:"User C", Level:"Standart"},
  {email: "userd@gmail.com",nama:"User D", Level:"Standart"},
  {email: "usere@gmail.com",nama:"User E", Level:"Admin"},
  {email: "userf@gmail.com",nama:"User F", Level:"Standart"}
];
var filter = "Level";
var keyword = "Standart";

//--------Search


console.log(data);

Andrew Li · Accepted Answer · 2016-10-31T04:08:05.270

10

You can use the Array.prototype.filter function which takes a callback and filters accordingly. Per the documentation:

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

The callback, which is the provided function, takes three arguments. From the documentation:

callback

Function is a predicate, to test each element of the array. Return true to keep the element, false otherwise, taking three arguments:

element

The current element being processed in the array.

index

The index of the current element being processed in the array.

array

The array filter was called upon.

We may use element to check the current element and test if it should be filtered or not, like so:

var data = [
  {email: "usera@gmail.com",nama:"User A", Level:"Super Admin"},
  {email: "userb@gmail.com",nama:"User B", Level:"Super Admin"},
  {email: "userc@gmail.com",nama:"User C", Level:"Standart"},
  {email: "userd@gmail.com",nama:"User D", Level:"Standart"},
  {email: "usere@gmail.com",nama:"User E", Level:"Admin"},
  {email: "userf@gmail.com",nama:"User F", Level:"Standart"}
];
var filter = "Level";
var keyword = "Standart";

var filteredData = data.filter(function(obj) {
 return obj[filter] === keyword;
});

console.log(filteredData);

Here, we use a callback (the test) that checks if the current element (obj)'s property specified in filter is strictly equal to keyword. If it passes, it is kept, and thus all objects with property Level with vale Standart are kept. You can also shorten this with ES6 arrow functions:

var filteredData = data.filter((obj) => obj[filter] === keyword);

This is just shorthand for the above. It is effectively the same, returning true or false based on if the current element's Level property is strictly equal to keyword.

edited Oct 31 '16 at 04:08

answered Oct 31 '16 at 04:01

Andrew Li

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how if the keyword is a wildcard ? in mysql using %keyword% can i using /^keyword/ ? – Renandatta Rooziq Oct 31 '16 at 04:26
@RenandattaRooziq That's really out of my expertise. If you mean a regex, see [here](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/test). It can be applied like so: `/regex/.test(obj[filter])`. – Andrew Li Oct 31 '16 at 04:28
yeah, i mean regex – Renandatta Rooziq Oct 31 '16 at 04:30
@RenandattaRooziq Then yes. Instead of `obj[filter] === keyword` do `/^keyword/.test(obj[filter])` – Andrew Li Oct 31 '16 at 04:31
i'm sorry, but it doesn't work, here my script https://jsfiddle.net/renandatta/yhdyb5bg/5/ – Renandatta Rooziq Oct 31 '16 at 04:35
@RenandattaRooziq What is that you are trying to filter out? What's the desired end result? – Andrew Li Oct 31 '16 at 04:36
i want to search that array like in mysql, in mysql i using WHERE LIKE "%keyword%". i have Level : "Standart", if i search "Stand", i want result all element with level Standart – Renandatta Rooziq Oct 31 '16 at 04:54
1

@RenandattaRooziq Something like this? https://jsfiddle.net/yhdyb5bg/11/ - use `JSON.stringify` as necessary. – Andrew Li Oct 31 '16 at 05:02

score 1 · Answer 2 · answered Oct 31 '16 at 03:59

You can use the array.prototype.filter() function to filter through the array with a custome function:

var data = [
  {email: "usera@gmail.com",nama:"User A", Level:"Super Admin"},
  {email: "userb@gmail.com",nama:"User B", Level:"Super Admin"},
  {email: "userc@gmail.com",nama:"User C", Level:"Standart"},
  {email: "userd@gmail.com",nama:"User D", Level:"Standart"},
  {email: "usere@gmail.com",nama:"User E", Level:"Admin"},
  {email: "userf@gmail.com",nama:"User F", Level:"Standart"}
];
var filter = "Level";
var keyword = "Standart";

//--------Search
var filtered_data = data.filter(function(item) {
    return item[filter] == keyword
})

console.log(filtered_data);

score 0 · Answer 3 · answered Oct 31 '16 at 03:57

You can use the filter() function to filter out the elements based on a condition like this:

> var data = [
  {email: "usera@gmail.com",nama:"User A", Level:"Super Admin"},
  {email: "userb@gmail.com",nama:"User B", Level:"Super Admin"},
  {email: "userc@gmail.com",nama:"User C", Level:"Standart"},
  {email: "userd@gmail.com",nama:"User D", Level:"Standart"},
  {email: "usere@gmail.com",nama:"User E", Level:"Admin"},
  {email: "userf@gmail.com",nama:"User F", Level:"Standart"}
];
> var newData=data.filter(function(x) { return x.Level == 'Standart'})
> console.log(JSON.stringify(newData))
[{"email":"userc@gmail.com","nama":"User C","Level":"Standart"},{"email":"userd@gmail.com","nama":"User D","Level":"Standart"},{"email":"userf@gmail.com","nama":"User F","Level":"Standart"}]

score 0 · Answer 4 · answered Oct 31 '16 at 04:03

You could just use the array filter method to accomplish your goal here.

var data = [{
  email: "usera@gmail.com",
  nama: "User A",
  Level: "Super Admin"
}, {
  email: "userb@gmail.com",
  nama: "User B",
  Level: "Super Admin"
}, {
  email: "userc@gmail.com",
  nama: "User C",
  Level: "Standart"
}, {
  email: "userd@gmail.com",
  nama: "User D",
  Level: "Standart"
}, {
  email: "usere@gmail.com",
  nama: "User E",
  Level: "Admin"
}, {
  email: "userf@gmail.com",
  nama: "User F",
  Level: "Standart"
}];
var filter = "Level";
var keyword = "Admin";

var filteredArray = data.filter((item) => item[filter] === keyword);
console.log(filteredArray);

Search array of object with filter and keyword

4 Answers4

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