Learning Assembly num function

Question

So I'm learning Assembly and i have come across this code:

movl num(,%eax,4), %eax

Can someone explain what that num() function is?

score 2 · Accepted Answer · answered Oct 27 '16 at 18:26

2

It is not a function, it is an element of the AT&T assembly syntax. That line means "move 32-bit value at address eax*4 + num to eax".

In Intel syntax it would be mov eax, [eax*4 + num].

answered Oct 27 '16 at 18:26

glauxosdever

Oh wow i didnt realize this was the AT&T assembly syntax. The more you know! – Newb18 Oct 27 '16 at 18:40

1 Answers1