Can't find a way to write a sequence 1,2,3,4,..,K,1,2,3,...,K, where K is user entered number

Question

This is the loop.

    for(m=0; m<10; m++){
        for (i=0; i<=K; i++) {
            A[i] = i;
     }
   }

And this is print code.

System.out.println("A:");
    for (i=0; i<20; i++) {
        System.out.printf("%.1s\t", A[i]);
        if (i==9) System.out.println();
    }

If user enter K as 3 then result is:

A:
0   1   2   3   0   0   0   0   0   0   
0   0   0   0   0   0   0   0   0   0

But it should be like

A:
0   1   2   3   0   1   2   3   0   1   
2   3   0   1   2   3   0   1   2   3

Hint: Use the modulo `%` operator. – QBrute Oct 27 '16 at 10:23 — QBrute, Oct 27 '16 at 10:23

score 0 · Answer 1 · answered Oct 27 '16 at 10:26

0

System.out.println("A:");
    for (i=0; i<20; i++) {
        System.out.printf("%.1s\t", A[i]%(K+1));
        if (i==9)
          System.out.println();
    }

answered Oct 27 '16 at 10:26

Vyacheslav

26,359
19
112
194

score 0 · Answer 2 · answered Oct 27 '16 at 10:31

0

Your loops are wrong. You only altered the first K+1 members of the array.

answered Oct 27 '16 at 10:31

Tung

1
3

score 0 · Answer 3 · answered Oct 27 '16 at 10:33

0

The index "i" is inside an inner loop so it start from 0 for ech iteration of "m". You are overwriting the first K items of the array A

Maybe you want want write a code like this:

ind = 0;
for(m=0; m<10; m++)
{
        for (i=0; i<=K; i++)
        {
            A[indx] = i;
            indx++;
        }
}

answered Oct 27 '16 at 10:33

alessio.zatti

9
2

minor typo: it should be `indx` not `ind` :) – GameDroids Oct 27 '16 at 10:48

score 0 · Answer 4 · answered Oct 27 '16 at 10:40

The order of your numbers is alright, the problem is the Array A or better, the index when you add your numbers to that array.

for (i=0; i<=K; i++)
     A[i] = i;

here you loop through A starting at A[0] and finishing at A[K]. And you do that 10 times:

  for(m=0; m<10; m++)

So: either you use the % (modulo) operator as QBrute suggested in his comment or you find yourself a more "global" index. For example

 int j = 0;
 for(int m = 0; m < 10; m++){
    for(i = 0; i <= K; i++){
        A[j++] = i;
    }
 }

In this case you have to make sure your array is of the correct size: You want 10 times the numbers from 0 to K, so your A would be int[(K+1)*10] , while the +1 is because you loop from i=0 to i=K (which makes K+1 iterations)

If I may give you some advices: variables and methods should always start with a small letter (`a` not `A` and `k` not `K`). Then give those variables some useful names like `userInput` instead of `k`, so you will know what they are used for. And lastly: always use braces `{ }` in `if` statements or `loops`. If you leave out those braces, it may be convenient and faster to write, but it is an unnecessary source for errors. Believe me :) its easier that way — GameDroids, Oct 27 '16 at 10:46

Jobin · Answer 5 · 2016-10-28T06:57:20.733

Code

    int userEnteredVal = 3;

    Integer[] smallArr = new Integer[userEnteredVal + 1];
    Integer[] outpuptArr = new Integer[20];

    for (int i = 0; i <= userEnteredVal; i++) {
        smallArr[i] = i;
    }

    for (int index = 0; index < 20; index += (userEnteredVal + 1)) {
        System.arraycopy(smallArr, 0, outpuptArr, index, smallArr.length);
    }

    for (int i = 0; i < outpuptArr.length; i++) {
        System.out.printf(outpuptArr[i] + "   ");

        if (i == 9) {
            System.out.printf("\n");
        }
    }

OutPut

0   1   2   3   0   1   2   3   0   1   
2   3   0   1   2   3   0   1   2   3

hope this will help.

Can't find a way to write a sequence 1,2,3,4,..,K,1,2,3,...,K, where K is user entered number

5 Answers5