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Spring HATEOAS works great at linking to another method in the same application. For example:

Greeting greeting = new Greeting(String.format(TEMPLATE, name));
greeting.add(linkTo(methodOn(GreetingController.class).greeting(name)).withSelfRel());

If one were to implement a microservice architecture, then most of the linked methods would be part of a different service and different Java project.

The only way I can see of to add a link to a method outside of the existing project is to hard-code in the URL (or put it in an external configuration).

Are there any alternatives to dynamically create the URL? For instance, is it possible to use Spring HATEOAS in conjunction with a Service Registry (like Eureka)?

  • _" then most of the linked methods would be part of a different service and different Java project"_ Absolutely not. Can you explain your reasoning? – a better oliver Oct 27 '16 at 07:41
  • @zeroflagL Using a microservice architecture, all services are developed and deployed independently of each other. http://microservices.io/patterns/microservices.html –  Oct 31 '16 at 15:00
  • Sure, but why would a resource of one microservice point to a resource of another one? And even if, why would one service create the URL to / for another one? That makes no sense. And yes, Spring offers integration with Eureka. – a better oliver Oct 31 '16 at 15:24
  • Simple example is a Customer service and an Order service. They are 2 separate microservices. On the Order service, you may want to add a link to the Customer service so the client knows how to access information on the Customer. –  Oct 31 '16 at 15:28
  • Good example. But if you create an order for a customer you already need a link to the customer. The order service does not create one. – a better oliver Nov 02 '16 at 07:34
  • I know this is old, but still relevent, what if you are running in AWS and you generate a file in S3 and want to return a pre-signed URL for example. Would you return the full URI to this in HATEOS still with a restful response or return a 202 and set the location header? – berimbolo Jul 31 '20 at 06:45
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    how is it that there is still no answer? – RexSplode Oct 12 '20 at 14:59

1 Answers1

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Yes, you can use Spring HATEOAS in conjunction with a service registry like Eureka to dynamically create URLs for linking to methods in different services within a microservice architecture.

In a microservice architecture, each service typically registers itself with the service registry, such as Eureka, and provides its service information (like host, port, and service name). Other services can then discover and communicate with these registered services through the registry.

To dynamically create URLs using Spring HATEOAS and a service registry, you can follow these steps:

  1. Configure your microservices to register themselves with the service registry (e.g., Eureka). This involves adding the necessary dependencies and configuration to your microservice projects.

  2. Enable service discovery in your Spring HATEOAS application by configuring the service registry client. You can use Spring Cloud Netflix Eureka, which integrates Eureka with Spring applications. Add the necessary dependencies to your project and configure the Eureka client to connect to the service registry.

  3. In your Spring HATEOAS application, when creating links to methods in other services, you can use the service name registered in the service registry along with the method path or endpoint. Instead of hard-coding the URL, you can construct it dynamically using the service name and other details obtained from the service registry.

Here's an example of how you can dynamically create URLs using Spring HATEOAS and Eureka:

// Assuming you have a service registry client configured (e.g., Spring Cloud Netflix Eureka)

// Inject the DiscoveryClient to retrieve service information from the registry
@Autowired
private DiscoveryClient discoveryClient;

// ...

// Get the instances of the target service from the service registry
List<ServiceInstance> instances = discoveryClient.getInstances("target-service-name");

// Assuming there's only one instance of the target service running
if (!instances.isEmpty()) {
    ServiceInstance targetInstance = instances.get(0);

    // Construct the base URL using the service instance information
    String baseUrl = String.format("http://%s:%d", targetInstance.getHost(), targetInstance.getPort());

    // Create the URL dynamically by appending the endpoint or method path
    String targetUrl = baseUrl + "/target-endpoint";

    // Create the link using the dynamically generated URL
    Link targetLink = linkTo(methodOn(GreetingController.class).greeting(name)).toUriComponentsBuilder()
            .uri(URI.create(targetUrl))
            .build()
            .toUri();

    greeting.add(new Link(targetLink.toString(), "target"));
}

In the above example, the target-service-name represents the name of the service you want to link to. You can retrieve the service instance(s) using the DiscoveryClient and construct the URL dynamically by combining the host, port, and endpoint.

This way, you can create links to methods in different services based on the information obtained from the service registry, rather than hard-coding the URLs.

Issam EL-GUERCH
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