Django - server code response in JsonResponse

Question

Is it possible to add server response code to JsonResponse ? I need server to reply with 404 in some circumstances.

I have following view

def CreateOrAuth(request):
try: 
    username = request.POST.get("username")

    queryset = User.objects.get(username=username)

except Exception as e:
    return JsonResponse({'status': 'user with {} not exist'.format(username)})

And I want to add 404 server code here

please check this answer: http://stackoverflow.com/a/35059936/3065081 — Hamad AlGhanim, Oct 23 '16 at 11:14
Possible duplicate of [Django json response error status](http://stackoverflow.com/questions/35059916/django-json-response-error-status) — GwynBleidD, Oct 23 '16 at 12:31

score 3 · Answer 1 · answered Oct 23 '16 at 12:30

3

Yes, you can. Just pass additional parameter status to JsonResponse:

return JsonResponse({'status': 'user with {} not exist'.format(username)}, status=404)

answered Oct 23 '16 at 12:30

GwynBleidD

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Django - server code response in JsonResponse

1 Answers1