How do I store an unsigned short into a char array? C language

Question

I'm a beginner in C language, I was wondering how I store an unsigned short into a char array?

unit16_t is unsigned short, and below is my code.

uint16_t  combined = 1234;
char echoPrompt[] = {combined};

EDIT:

Sorry for being unclear I need echoPrompt to be a char array and combined needs to be an integer. I am passing echPrompt as a char array to a UART_write which required a char array.

You'll need to add more info on why you need to do this. Short answer is why not use an array of shorts? — John3136, Oct 16 '16 at 06:17
Please give more details about the issue. There are at least two different methods depending on the details. — GMichael, Oct 16 '16 at 06:30

score 2 · Answer 1 · answered Oct 16 '16 at 06:30

You cannot pass an array to a function. You can pass a pointer. Pointers are not arrays.

If your UART_write looks anything like any of the standard C/POSIX functions write, fwrite etc, you need

  result = UART_write (..., 
        (char*)&combined, 
        sizeof(combined), ...);

There is no need in a char array.

score 1 · Answer 2 · answered Oct 16 '16 at 06:35

if I understood correctly, you want to save each upper and lower 1 byte of short in char array.

well, why don't you just use union?

typedef struct uint16_s{ 
    char upper; 
    char lower;
} uint16_s;

typedef union uint16_u{
    uint16_s sBuf;
    uint16_t tBuf;
} uint16_u;

uint16_u combined;
combined.tBuf = 1234;
char echoPrompt[] = {combined.sBuf.upper, combined.sBuf.lower};

How do I store an unsigned short into a char array? C language

2 Answers2