How to know the folder size in a zipfile

Question

I know that you can get the size in bytes of a file in a ZIP file using the .file_size method But is there any what I can get the size of a folder instead?

Ex:

import zipfile, os

os.chdir('C:\\')    
zp= zipfile.ZipFile('example.zip')

spamInfo = zp.getinfo('spam.txt')    #Here, Instead of a file I'd like to put a folder
spamInfo.file_size

zp.close()

You might need to loop for the files in the folder. Then get the info with zp.getinfo('file'). Then just increase a variable with the file_size each time. — Mirage, Oct 10 '16 at 07:11
`sum(zp.getinfo(filename).file_size for filename in folder)`? — Peter Wood, Oct 10 '16 at 07:13
Sorry for the dumb question, I'm new in this but what's the correct way of writing a folder. Example. If I have a folder named 'Drawings' on the zip file. should I put = > for filename in '\\Drawings'? — tadm123, Oct 10 '16 at 21:00

score 18 · Accepted Answer · edited Oct 18 '20 at 18:14

18

import zipfile

zp = zipfile.ZipFile("example.zip")

size = sum([zinfo.file_size for zinfo in zp.filelist])
zip_kb = float(size) / 1000  # kB

edited Oct 18 '20 at 18:14

Martin Thoma

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answered Oct 10 '16 at 07:22

Naresh Chaudhary

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3

You don't need to build a list, `sum` will work with the comprehension expression. – Peter Wood Oct 14 '16 at 09:27
1

This only work for reliable zip sources, it is no reliable for user/attacker-origin source, for that you have to physically read through the files - read and count bytes as you go. – jave.web Nov 07 '20 at 12:53
Hi, is there any way to vectorize this instead of the for loop and get the output in a dataframe? – Rohan Apr 12 '23 at 07:39

How to know the folder size in a zipfile

1 Answers1