how to assign hex values into char type without null termination?

Question

I would like to assign hex values into char type. Due to null (\x00) character, I cannot assign all hex values. Just 4 character can be assigned. How to assign all hex values in (char*)data ??

unsigned char data[100];
sprintf((char*)data,"\x30\x29\x02\x01\x00\x04\x06\x70\x75\x62\x6c\x69\x63\xa0");

Answer 1

Since you have all your hex numbers available at compile time, you can assign them using curly brace initializer instead of a string literal:

unsigned char data[] = {
    0x30, 0x29 ,0x02, 0x01, 0x00, 0x04, 0x06,
    0x70, 0x75, 0x62, 0x6c, 0x69, 0x63, 0xa0
};

Answer 2

In C, code cannot assign multiple values of an array with one assignment. Code can initialize as is this good answer.

Use a loop or memcpy() to assign multiple values.

unsigned char data[100];
#define SOURCE_DATA ("\x30\x29\x02\x01\x00\x04\x06\x70\x75\x62\x6c\x69\x63\xa0")
#define SOURCE_SIZE (sizeof SOURCE_DATA - 1)
memcpy(data, SOURCE_DATA, SOURCE_SIZE);