Does vector.erase resize the vector object so that I can measure the reduced size with vector.size()?
for example;
vector<int> v(5);
v = {1,2,3,4,5};
and I want to delete 4 by;
v.erase(v.begin()+4);
Does my vector object v have a size of 4 now. In other words is v.size() == 4 after this operation?
Yes, size is decreased as you erase elements.
Don't be afraid to test yourself though, by writing a minimal example, like this :) :
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<int> v(5);
v = {1,2,3,4,5};
cout << v.size() << endl;
v.erase(v.begin()+4);
cout << v.size() << endl;
return 0;
}
you would get:
gsamaras@gsamaras-A15:~$ g++ -Wall -std=c++0x main.cpp
gsamaras@gsamaras-A15:~$ ./a.out
5
4
And we would expect that right? I mean the ref says:
Return size
Returns the number of elements in the vector.
This is the number of actual objects held in the vector, which is not necessarily equal to its storage capacity.
