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I am having trouble getting access to a simple uploaded file which I need to parse without saving it. Since the file does not need to be saved I have not made a model for it. All other threads on this state the html form encoding type, name tag are the primary reasons why request.FILES is not appearing-- I have addressed these and still there is no request.FILES being captured.

forms.py

class DataExportForm(forms.Form):
    docfile = forms.FileField(label='Select a template',help_text='Extracted info will be returned')

HTML

<html>
<body>
<form action="." method="post" enctype="multipart/form-data">{% csrf_token %}

<tr><th><label for="id_docfile">Select a template:</label></th><td><input id="id
_docfile" name="docfile" type="file" />
<button type="submit" name="action">Upload</button>
<br /><span class="helptext">Zip file wil
l be returned with data</span></td></tr>   
</form>
</body>
</html>

views.py

if request.method=='POST':        
    form=DataExportForm(request.POST, request.FILES)
    if form.is_valid():
        #Code runs OK till here but request.FILES does not exist. 
        groupList=extractTemplateNames(request.FILES['file'].read())

I guess if I get it working I may find the file not in request.FILES['file'] but in request.FILES['docfile'] but at this point request.FILES does not exist. Any tips to solve this would be appreciated.

allcaps
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petko
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2 Answers2

2

Most likely, problem is just that you are trying to access file using wrong name. Field on form has name docfile. Same name it will have in request.FILES array.

Possibly, you simply misunderstood an error message saying that there is no file in FILES.

And form.is_valid access FILES array correctly, that is why form is considered to be valid.

Viktor S.
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0

So apparently the only thing missing was looking for request.FILES['docfile']

not request.FILES['file'] . It works! Hope this is helpful to someone

petko
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