strcmp() not working as expected

Question

echo($menuVal['icon']);
/* if($menuVal['icon'] !== 'fa-dashboard' ){
$menuHTML .= '<span class="ico fa fa-fw fa-chevron-right"></span>';
}*/
$cont=strcmp($menuVal["icon"],"fa-dashboard");
echo($cont);
if((strcmp($menuVal["icon"],"fa-dashboard")) != 0 ){
    $menuHTML .= '<span class="ico fa fa-fw fa-chevron-right"></span>';
}

in this code i'm trying to print the icon using php if it value is not equal to fa-dashboard,i think strcmp will produce an output zero if inputs are equal,but in this code strcmp is producing an output of 243 when both strings are equal and the if condition is worked when put 243 instead of 0.

i added the output obtained on below,i'm also checked the value of $menuVal['icon'] to check what it prints,

fa-dashboard 243fa-globe 768fa-puzzle-piece 3072fa-pie-chart
3072fa-gears 768fa-anchor -768

is there any error in this code?how can i fix that? any help will get appreciated..........!!!

the first iteration should not satisfy the condition (its `fa-dashboard` as shown in your output), all other icon values should, so whats the problem? — Kevin, Sep 28 '16 at 04:13
no one can reproduce that on our end, we can make assumptions based on that output example that you have. the first iteration should yield zero — Kevin, Sep 28 '16 at 04:21

score 1 · Accepted Answer · answered Sep 28 '16 at 04:49

Your checking if the entire string equals fa-dashboard which is not.

If fa-dashboard is always the first item you can use strncmp to match only the first n characters.

int strncmp ( string $str1 , string $str2 , int $len )

This function is similar to strcmp(), with the difference that you can specify the (upper limit of the) number of characters from each string to be used in the comparison.

strcmp() not working as expected

1 Answers1