Avoid repeating variable name in assignation

Question

I think I have seen a way to reduce this:

long_variable_name = long_variable_name.squeeze('i')

To something like this:

long_variable_name = &:squeeze('i')

But it doesn't work and I must be confusing. Just wondering if there is actually a way to do this ? Thanks

Crystal. Actually I hoped it would be the same in both. I always look for both as ruby is more documented. — Aurelien, Sep 26 '16 at 18:21
I'm curious why you need the string `long_variable_name`. What do you plan to do with it? (Perhaps it has something to do with *Crystal*, of which I know nothing). — Cary Swoveland, Sep 26 '16 at 18:25
You can google for both, but don't tag crystal questions with "ruby" on stackoverflow. Those are different languages and different stdlibs. — Sergio Tulentsev, Sep 26 '16 at 18:44

score 2 · Answer 1 · answered Sep 26 '16 at 18:13

2

Do you mean this?

variable.squeeze!('i')

Note the bang (!).

answered Sep 26 '16 at 18:13

spickermann

In the String class, `!` denotes the in-place modifying version. See [`squeeze!`](http://ruby-doc.org/core-2.3.1/String.html#method-i-squeeze-21). – tadman Sep 26 '16 at 18:15
In ruby, yes. Don't know about crystal :) – Sergio Tulentsev Sep 26 '16 at 18:15
Yes that is what I was looking for. Don't know why I remember this '&'. Thank you – Aurelien Sep 26 '16 at 18:22

1 Answers1