ui-grid get the current column (field) name from inside a custom sorting algorithm?

Question

Once you define custom sorting for a column like in Github and UI-Grid

How can you access the column from inside the algorithm?

var myAwesomeSortFn = function(a,b, rowA, rowB, direction){

       // "Need to access the name (field) of column being sorted here";
        var column = "No Idea"

       console.log("sorting by column " + column );

        if (a == b) return 0;
        if (a < b) return -1;
        if (a > b) return 1;


    };

Can you post the code where you are calling `myAwesomeSortFn`? — S. Baggy, Sep 25 '16 at 21:10

score 1 · Accepted Answer · answered Sep 27 '16 at 22:01

1

You could try the following...

{ field: 'lastName', displayName: 'Last Name', sortingAlgorithm: MyService.getSortingAlgorithm('lastName') },

Then define in a service (or in your scope if you prefer)

getSortingAlgorithm: function (columnName) {
    return function(a, b, rowA, rowB, direction) {
        console.log("sorting by column " + columnName);

        if (a == b) return 0;
        if (a < b) return -1;
        if (a > b) return 1;
    };  
}

answered Sep 27 '16 at 22:01

S. Baggy

950
10
21

This is what I'm currently doing, it works, but also means lots of time when you have over 40 columns, plus the maintainability cost when fields change. – MishaT Sep 29 '16 at 14:52
I'll mark this as accepted since it seems to be the only way to do it without modifying ui-grid, which we ended up doing to expose the column. – MishaT Oct 12 '16 at 22:40

ui-grid get the current column (field) name from inside a custom sorting algorithm?

1 Answers1