Extra argument 'method' in call

Question

Getting error while calling Alamofire request method in the latest version(4.0.0).

The syntax is:

Alamofire.request(urlString,method: .post, parameters: requestParams, encoding: .JSON, headers: [:])

the type of requestParam is [String:Any]

Did you try: `Alamofire.request(urlString, method: .post, parameters: requestParams, encoding: .JSON, headers: [:])` — netdigger, Sep 19 '16 at 11:37

score 70 · Accepted Answer · answered Sep 19 '16 at 17:23

70

I got the issue, I have to use JSONEncoding.default instead of .JSON, so the new syntax is

Alamofire.request(urlString,method: .post, parameters: requestParams, encoding: JSONEncoding.default, headers: [:])

answered Sep 19 '16 at 17:23

CMA

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Not fixed for me, I have written the same code for this :( – Sumeet Mourya Jun 19 '17 at 09:52
3

Now it gives for method argument post – Mansuu.... Jul 04 '17 at 06:49
2

it's working for me i have passed headers parameter with type HTTPHeaders.hope this will wok for you. – Hemant Solanki Aug 10 '18 at 07:55
I really think netiggers answer should be the accepted one. The underlying problem here is a red herring error message when a parameter has the wrong type. – Tom Schulz Sep 21 '18 at 11:17

netdigger · Answer 2 · 2016-09-21T09:56:03.753

50

I can only refer you to: https://github.com/Alamofire/Alamofire/issues/1508#issuecomment-246207682

Basically, if one of your parameters is of the wrong type, the swift compiler will assume you're using request(urlRequest:URLRequestConvertible) and then, the method is an extra argument

Go over that parameters again and make sure all is of correct type (Parameters?, ParameterEncoding, and HTTPHeaders)

edited Sep 21 '16 at 09:56

answered Sep 19 '16 at 11:49

netdigger

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2

Thanks, I got the issue the value of ParameterEncoding was wrong, I have to use JSONEncoding.default instead of .JSON . – CMA Sep 19 '16 at 17:19
2

This was what caused it to me , I used parameters as string instead of [String:String] – yehyatt May 21 '17 at 13:00
Your explanation is what people need. not a dumb response, "do this ...", Thanks! – TheFuquan Jul 23 '17 at 12:51
My first parameter was broken. I needed to change the `let urlString = "host"` to `static let urlString = "host"` because the `urlString` variable was attached to the class and I was writing a class function – simple_code Oct 17 '17 at 05:46
Thumbs up. One of the best answers on SO! – EmptyStack Feb 15 '18 at 09:13
This was my problem. The headers dictionary in my case, was actually [ String : Any ] when I thought it was [ String : String ] (HttpHeaders is just an alias for that). As soon as I forced the bad value to String it compiled. I was storing a token in userDefaults, and when I retrieved it I used object(forKey:) not string(forKey:). – Tom Schulz Sep 21 '18 at 11:16

score 18 · Answer 3 · answered Oct 25 '17 at 09:42

18

I was having the same issue, the problem is at parameters type, it should be of type [String: Any]. After I made this change, it worked for me.

 Alamofire.request(youUrl, method: .post, parameters: param as? [String: Any], encoding: JSONEncoding.default, headers: [:])
                .responseJSON { response in

answered Oct 25 '17 at 09:42

Xhulio Hasa

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Yes, Some Time we need to define the param. – Anup Gupta Jan 23 '18 at 13:39

score 10 · Answer 4 · answered Mar 16 '17 at 09:30

10

It means that some of the parameters type are wrong, check that you are sending these values:

url: String
method: HTTPMethod  (E.g: .post)
parameters: [String:Any]
encoding: ParameterEncoding  (E.g: JSONEncoding.default)
headers: [String: String]

answered Mar 16 '17 at 09:30

Andrea.Ferrando

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solved my problem, thank you. I don't know why swift does't show errors more clearly. – Ângelo Polotto Aug 09 '18 at 13:21
Remember put the correct type of data and avoid using nil! – Marlon Ruiz Mar 16 '19 at 18:18

score 10 · Answer 5 · answered Apr 03 '17 at 12:42

Updated for Swift 3:

let requestString = "https://thawing-inlet-46474.herokuapp.com/charge.php"
        let params = ["stripeToken": token.tokenId, "amount": "200", "currency": "usd", "description": "testRun"]

        Alamofire.request(requestString,method: .post, parameters: params, encoding: JSONEncoding.default, headers: [:]).responseJSON { (response:DataResponse<Any>) in

            switch(response.result) {
            case .success(_):
                if response.result.value != nil{
                    print("response : \(response.result.value)")
                }
                break

            case .failure(_):
                print("Failure : \(response.result.error)")
                break

            }
        }

score 7 · Answer 6 · answered Apr 30 '17 at 00:24

7

Make sure your parameters is [String: Any]

i.e

let parameters = ["foo": "bar"]

Not:

let parameters : Parameter = ["foo": "bar"]

answered Apr 30 '17 at 00:24

Ben

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This was my mistake, I assumed it could be `[AnyHashable: Any]`. – Dielson Sales Jul 05 '17 at 14:12

score 5 · Answer 7 · answered Aug 24 '18 at 06:33

You are getting that error because of the wrong data types.

Parameters Type should be [String : Any] and parameters type shouldn't be an optional.

Header Type should be [String : String] or nil and header type shouldn't be an optional as well.

Hope it helps. :-)

score 4 · Answer 8 · answered Oct 21 '16 at 15:16

4

I fixed this by ensuring my requestUrls are strings, and not URL types. Also I removed parameter arguments for when parameter was nil.

E.g.

Alamofire.request(requestUrl, method: .get, encoding: URLEncoding.default)

answered Oct 21 '16 at 15:16

Phil Hudson

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score 3 · Answer 9 · answered Nov 03 '16 at 08:12

3

Almofire methods changed in Swift 3 as the following:

Reorder parameters (url then method type).
Change Encoding Enum to be "JSONEncoding.default" for example.

answered Nov 03 '16 at 08:12

Ahmed Lotfy

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This was the recent issue for me. No hint that it was this, but it rather complained about the HTTPMethod. `.utf8` and similars won't do it, not even just `.default`. It has to be the long name: `JSONEncoding.default` – Alejandro Iván Apr 16 '18 at 18:31

score 3 · Answer 10 · answered Jan 05 '17 at 03:34

3

This is a family of functions that are very similar, which makes the compiler think you're trying to use a different function. Double check that ALL of the arguments you're supplying are the CORRECT TYPE that is expected. For example I was passing [String:Any] for the variant with headers, which expected [String:String] and got the same error.

answered Jan 05 '17 at 03:34

Matjan

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That's correct. I'm my case i was passing a [String] parameter instead of [String:String] and got the same error too. – mourodrigo Mar 09 '17 at 17:15

score 3 · Answer 11 · answered Oct 04 '17 at 18:29

3

It is always because im using optional variables in any of the parameters

answered Oct 04 '17 at 18:29

SoliQuiD

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I solved my problem with this hint... Great... Thanks – Ghanshyam Bagul Feb 03 '18 at 05:20

Abhishek Mishra · Answer 12 · 2018-11-03T06:24:51.377

I was facing same problem And try with all answer as previously post here, And then I got the solution and reason of this problem .

This is happened due to pass the wrong object parse in the request, and finally the solution --

theJSONText -- JSON string

urlStr -- URL string

 let urlEncoadedJson = theJSONText.addingPercentEncoding(withAllowedCharacters:.urlHostAllowed)
    let urls = NSURL(string:"urlStr\(urlEncoadedJson ?? "")")

let method: HTTPMethod = .get

Alamofire.request(urls! as URL, method: method, parameters: nil, encoding: JSONEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in

        switch(response.result) {
        case .success(_):

            if response.result.value != nil
            { 
              // write your code here
            }
            break

        case .failure(_):
            if response.result.error != nil
            {
                print(response.result.error!) 
            }
            break
        }

    }

Note - There is no param in my URL .

score 1 · Answer 13 · answered Jul 25 '17 at 11:19

1

My problem was in optional parameters in the headers that were not unwrapped.

answered Jul 25 '17 at 11:19

Jakub Vodak

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score 0 · Answer 14 · answered Feb 20 '19 at 06:06

Alamofire.request(url, method: .post, parameters: parameters, encoding: 
JSONEncoding.default, headers: [:]).responseJSON 
{ response in

            switch (response.result) {
            case .success:
                print(response)
                break
            case .failure:
                print(Error.self)
            }
        }

score 0 · Answer 15 · answered Jun 11 '19 at 07:18

0

just make sure all the parameters are in the correct format , most importantly the parameters must be in [String:Any] type array.

answered Jun 11 '19 at 07:18

Suraj Gaur

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Extra argument 'method' in call

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