how to solve "type Any has no subscript members" error?

Question

I have written code in swift 2.3 while converting to swift 3 i am getting error like "type Any has no subscript members"

let userDetail:Any = (GJCommon.sharedInstance.getUserInfo() as? NSDictionary)!

    print(userDetail)

    let userImage = (userDetail["Vehicle"]["bike_photo"] as? String)!

In this line i am getting error "let userImage = (userDetail["Vehicle"]["bike_photo"] as? String)!" Please help to do this.

I can see at least 6 questions with the same title in the "Related" section on the right. Are you sure that none of them helps to solve your problem? — Martin R, Sep 19 '16 at 07:47
Yes here my error is getting values from dictionary. no one cleared my doubt. — Vijay, Sep 19 '16 at 07:48
http://stackoverflow.com/questions/39466624/ambiguous-use-of-subscript-after-converting-to-swift-2-3/39466734#39466734 — Bhavin Bhadani, Sep 19 '16 at 07:48
what is the output of `GJCommon.sharedInstance.getUserInfo()`? — Bista, Sep 19 '16 at 08:02
Possible duplicate of [type any? has no subscript members](http://stackoverflow.com/questions/38956785/type-any-has-no-subscript-members) — Zeeshan, Sep 19 '16 at 08:25

score 1 · Answer 1 · answered Sep 19 '16 at 08:03

1

Try this:

if let userDetail = GJCommon.sharedInstance.getUserInfo() as? [String:AnyObject] {

    print(userDetail)

    let userImage = (userDetail["Vehicle"]["bike_photo"] as? String)!
}

answered Sep 19 '16 at 08:03

Bista

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let me know the result. – Bista Sep 19 '16 at 08:04
Thanks! its working if i am using NSDictionary insteadof [String:AnyObject] what about let userImage = (userDetail["Vehicle"]["bike_photo"] as? String)! – Vijay Sep 19 '16 at 09:42
Is there any possible to do like this please edit your answer and write that possible also please. – Vijay Sep 19 '16 at 09:43
`NSDictionary` instead of `[String:AnyObject] ` works? – Bista Sep 19 '16 at 09:45
getting same type any error in this line let userImage = (userDetail["Vehicle"]["bike_photo"] as? String)! – Vijay Sep 19 '16 at 09:49
what is the output of `print GJCommon.sharedInstance.getUserInfo()?` – Bista Sep 19 '16 at 09:55

score 1 · Answer 2 · answered Sep 19 '16 at 08:06

You are trying to access userDetail as an NSDictionary but it is of type Any.

As #Mr.UB said (beat me to it), change the first line to:

let userDetail = (GJCommon.sharedInstance.getUserInfo() as? NSDictionary)!

And it should then compile, although other parts of your code may then object. More context would be useful.

However your use of ! to force unwrap this and a later result is a bad idea. Use conditional unwrapping to catch errors more gracefully and avoid an App that crashes regularly.

how to solve "type Any has no subscript members" error?

2 Answers2