How does Regex work in Boost Regex C++

Question

I am currently using Boost Regex library and am trying to get a function called arguments in C++. For instance, I have a page with HTML and there a JavaScript function called, we will call it something like

XsrfToken.setToken('54sffds');

What I currently have, which isn't working.

std::string response = request->getResponse();

boost::regex expression;

if (type == "CSRF") {
    expression = {"XsrfToken.setToken\('(.*?)'\)"};
}

boost::smatch results;

if (boost::regex_search(response, results, expression)) {
    std::cout << results[0] << " TOKEN" << std::endl;
}

Where response is the HTML web page, and expression is the regex. The conditional statement is running, therefore I think something is wrong with my regex, but I do not know.

[EDITED]

Forgot to mention that that regex was extracted from PHP and works in a PHP regex checker/debugger

Any chance to read the docs? http://www.boost.org/doc/libs/1_53_0/libs/regex/doc/html/index.html — Serge, Aug 31 '16 at 22:28
I tried reading the docs, not very well documented in my opinion. — Kurieita, Aug 31 '16 at 22:29

score 2 · Accepted Answer · answered Aug 31 '16 at 22:54

Your mistake not in a regex syntax though the ? is redundant after *, but in C++ string constant literal: the backslash char should be escaped with backslash:

#include <boost/regex.hpp>
#include <iostream>
#include <string>

std::string response("XsrfToken.setToken('ABC')");
boost::regex expression("XsrfToken.setToken\\('(.*?)'\\)");

int main() {

    boost::smatch results;

    if (boost::regex_search(response, results, expression)) {
        std::cout << results[0] << " TOKEN" << std::endl;
    }
}

How does Regex work in Boost Regex C++

1 Answers1