Python Float to String TypeError

Question

I am writing a temperature converter for fun and everything seems to be working except I am getting a 'TypeError: Can't convert 'float' object to str implicitly' message. From what I can tell I am converting it to a string after the fact, can anyone tell me what I am doing wrong?

I looked this this question previously "Can't convert 'float' object to str implicitly"

def tempconverter(startType,Temp):
    #conversion types: c -> f c-> K , f -> c, f -> k, k -> c, k -> f
    # maybe have them select only their beginning type then show
    # all temp types by that temperature

if startType[0].lower() == 'c':
    return  ('Your temperature ' + Temp +'\n'
            + 'Farenheight: ' + ((int(Temp)*9)/5)+32 + '\n'
            + 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ##
            )
elif startType[0].lower() == 'f':
    #commented out until first is fixed
    #return  ((int(Temp)-32)*5)/9
    return Temp
elif startType[0].lower() == 'k':
    return  Temp

print('Welcome to our temperature converter program.')
print('''Please enter your temperature type:
         C = Celsius
         F = Farenheight
         K = Kelvin''')
sType = input('> ')

print('Please enter the temperature you wish to convert.')
sTemp = input('> ')

print(tempconverter(sType,sTemp))

You should use %s and %i escapes for your formatting. Looks cleaner and I bet will make your problem easier to trouble shoot if not fix it — Angus, Aug 29 '16 at 21:12
@Angus: I wouldn't recommend that; the `%i` auto-rounding tends to cause more confusion than it's worth. I'd recommend sticking to the `format` method, or `%s` for everything. — user2357112, Aug 29 '16 at 21:16
I will look into using string formatting, I probably should have been using that but this way seemed less complicated? I dont really have an excuse to not do it. — Taku_, Aug 29 '16 at 21:19

score 2 · Accepted Answer · answered Aug 29 '16 at 21:30

2

In the line of code:

+ 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ##

The error is caused by this part of it:

Temp+ 273.15

Temp is a string. You can't add a string and a number together.

answered Aug 29 '16 at 21:30

John Gordon

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I tried int() conversion before and it didnt work.. dammit Oh well Thanks! that fixed it. Now I am going to convert this to string formatting – Taku_ Aug 29 '16 at 21:34

score 1 · Answer 2 · answered Aug 29 '16 at 21:12

1

In this calculation:

((int(Temp)*9)/5)+32

You are not converting your result to str.

Also, you have spelled "Fahrenheit" incorrectly.

answered Aug 29 '16 at 21:12

kindall

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That isnt the line of code its erroring on? also I know i spelled it wrong. – Taku_ Aug 29 '16 at 21:15
_That isnt the line of code its erroring on_ Perhaps you'd care to let us know what line of code it _is_ erroring on? – John Gordon Aug 29 '16 at 21:26
Its in my code above.. + 'Kelvin: ' + str((Temp+ 273.15)) ## I get the error here ## – Taku_ Aug 29 '16 at 21:27
Ah, now I see. My bad. – John Gordon Aug 29 '16 at 21:29

Python Float to String TypeError

2 Answers2