how i get ownership property of Method: TRttiMethod in OnInvoke method of TVirtualInterface class?
I have this interface:
IPerson = interface(IInvokable)
['{45CE428C-F880-4D61-A2C1-0F3CB47130B5}']
procedure SetName(const Value: string);
function GetName(): string;
[TEntityField('Field Name Here')]
property Name: string read GetName write SetName;
end;
and this class:
type
TVirtualEntity<T: IInvokable> = class(TVirtualInterface)
public
constructor Create(); reintroduce; overload;
end;
constructor TVirtualEntity<T>.Create;
begin
inherited Create(TypeInfo(T));
Self.OnInvoke :=
procedure(Method: TRttiMethod; const Args: TArray<TValue>; out Result: TValue)
var
attributes: TArray<TCustomAttribute>;
attributesManager: TAttributesManager;
entityFieldAttribute: TEntityField;
begin
attributesManager := TAttributesManager.Create(Method.GetAttributes);
try
if attributesManager.HasAttribute<TEntityField>() then
begin
Result := attributesManager.GetAttribute<TEntityField>.FieldName;
end;
finally
attributesManager.Free;
end;
end;
end;
I'd like to get TRttiProperty of Method: TRttiMethod, but how? if i change the interface to:
IPerson = interface(IInvokable)
['{45CE428C-F880-4D61-A2C1-0F3CB47130B5}']
procedure SetName(const Value: string);
[TEntityField('Field Name Here')]
function GetName(): string;
property Name: string read GetName write SetName;
end;
the code works, but i'd like to user interfaces like this:
IPerson = interface(IInvokable)
['{45CE428C-F880-4D61-A2C1-0F3CB47130B5}']
procedure SetName(const Value: string);
function GetName(): string;
[TEntityField('Field Name Here')]
property Name: string read GetName write SetName;
end;