For Loop at Python

Question

My goal is to create a for-loop code that will return an output like the following:

list(indicator.values())[0],
list(indicator.values())[1],
list(indicator.values())[2],
list(indicator.values())[3],
...
...
list(indicator.values())[98],
list(indicator.values())[99],

However when I run the code below, I receive an error message 'TypeError: 'int' object is not iterable'. How can I fix this so I can get the intended result?

x = 100
for item in x:
    list(indicator.values())[item]

```for item in range(x)```. But the style of this code is worrisome at least. — sascha, Aug 24 '16 at 00:10
Possible duplicat of http://stackoverflow.com/questions/19523563/python-typeerror-int-object-is-not-iterable — Oncodeeater, Aug 24 '16 at 00:11

score 3 · Accepted Answer · answered Aug 24 '16 at 00:19

3

Use this code:

x = 100
for item in range(x):
    print(list(indicator.values())[item])]

answered Aug 24 '16 at 00:19

Peter234

1,052
7
24

score 0 · Answer 2 · answered Aug 24 '16 at 00:15

0

Use range() with for to iterate it from 0 to 100. For example:

for i in range(100):
    print i
# prints number from 1 to 100

answered Aug 24 '16 at 00:15

Moinuddin Quadri

46,825
13
96
126

score 0 · Answer 3 · answered Aug 24 '16 at 00:16

0

read this document

and try this code

x = range(0,100)

for item in x:
    list(indicator.values())[item]

answered Aug 24 '16 at 00:16

widget widget

11
3

Josiah Coad · Answer 4 · 2016-08-24T03:31:51.370

0

For -- in -- is python's way of iterating (going through) something iterable (something that can be gone through). For example a list and a dictionary are iterable. The range function creates a list with given parameters, making an integer (which is not itself iterable) iterable.

edited Aug 24 '16 at 03:31

answered Aug 24 '16 at 03:26

Josiah Coad

325
4
11

For Loop at Python

4 Answers4