Groovy XmlSlurper: Find attribute name by attribute value in XML

Question

How can I find an attribute name in XML structure by attribute value using Groovy XmlSlurper/XmlParser. Let's say we have XML:

<root>
    <item id="Correction">
        <desc value_err="Error_3"></desc>
    </item>
    <item id_err="Error_2">
        <desc />
    </item>
</root>

I need to find attribute name by value (Initial task: find list of nodes where attribute value like 'Error_'). e.g "Error_2" -> id_err and "Error_3" -> value_err

The only solution I found iteration through all Node attributes map. Is there any GPath for it?

Small remark: we're not able to change structure of XML. This is external exception API.

What have you tried? What output do you expect? It's hard to tell from the question which bit you're struggling with — tim_yates, Aug 22 '16 at 09:08
I want to find the list of nodes (`groovy.util.slurpersupport.GPathResult`) where attribute value like 'Error_'. Then it will be processed by Error engine. — Alex, Aug 22 '16 at 09:23

score 6 · Accepted Answer · answered Aug 22 '16 at 15:37

You can just do a depth-first search of the XML tree:

def xmlString = '''<root>
    <item id="Correction">
        <desc value_err="Error_3"></desc>
    </item>
    <item id_err="Error_2">
        <desc />
    </item>
</root>'''

import groovy.xml.*

def xml = new XmlSlurper().parseText(xmlString)

def nodes = xml.'**'.findAll { node ->
    node.attributes().find { it.value.startsWith 'Error_' }
}

Groovy XmlSlurper: Find attribute name by attribute value in XML

1 Answers1