Django URL and Views

Question

Since this below method of Mapping Django Url from a view is depreciated in Django 1.9 and above

url(r'^contact/$', 'newsletter.views.contact', name='contact'),

url(r'^about/$', 'home.views.about', name='about'),

And this is what is currently in place

from newsletter import views'

url(r'^about/$', 'views.about', name='about'),

How do i Map my url for 2 different app views

from home import views

from newsletter import views

url(r'^home/$', 'views.home', name='home'), #located in home

url(r'^about/$', 'views.about', name='about'), #located in newsletter

Mapping like i did above will result to an error so i need help. New to Django

try from home import views as home_views – Windsooon Aug 20 '16 at 11:38 — Windsooon, Aug 20 '16 at 11:38

score 1 · Accepted Answer · answered Aug 20 '16 at 13:01

I don't understand what you mean by using a fully qualified module name being deprecated since it is a core python construct. But you can manage two different modules containing submodules with the same name by binding them to different aliases using the "import as" statement.

Example:

from home import views as home_view
from newsletter import views as news_view

Then you can use the aliases home_view and news_view to reference each module instead of views, throughout the declared namespace.

You can take a look at the import statement syntax in the Python docs here:

If the requested module is retrieved successfully, it will be made available in the local namespace in one of three ways:

If the module name is followed by as, then the name following as is bound directly to the imported module.

If no other name is specified, and the module being imported is a top level module, the module’s name is bound in the local namespace as a reference to the imported module

If the module being imported is not a top level module, then the name of the top level package that contains the module is bound in the local namespace as a reference to the top level package. The imported module must be accessed using its full qualified name rather than directly

The question is about passing a string that is later resolved by Django. In newer versions Django expects a function object and won't resolve a string with the full path to the function object. — knbk, Aug 20 '16 at 19:01

score 0 · Answer 2 · answered Aug 20 '16 at 11:38

0

Try:

from home import views as home_views

from newsletter import views

url(r'^home/$', 'home_views.home', name='home'), #located in home

url(r'^about/$', 'views.about', name='about'), #located in newsletter

answered Aug 20 '16 at 11:38

Windsooon

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Thanks. That was helpful – Phexcom Aug 20 '16 at 20:46

score 0 · Answer 3 · answered Aug 20 '16 at 19:00

0

As an alternative you can only import the view functions:

from home.views import home
from newsletter.views import about

urlpatterns = [
    url(r'^home/$', home, name='home'),
    url(r'^about/$', about, name='about'),
]

answered Aug 20 '16 at 19:00

knbk

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Django URL and Views

3 Answers3