hex string to decimal conversion

Question

I need to convert the string of hex to decimal in java..

My hex value is "00000156A56BE980".

My required output is 1471654128000

I have done the following in java,

public static void main (String args [])
{
  String hexValue = " 00000156A56BE980 ";
  Integer result = Integer.parseInt(hexValue, 16);
 System.out.println(result);
}

but I am getting the following error,

Number format Exception for input string "00000156A56BE980"

I have tried by giving long also the same error coming.. For other hex value it's coming but when we give hex string of larger value it shows the error.

How can we convert this number to decimal? Can anyone solve this issue for me?

Answer 1

Try it like so

import java.math.*;

class Main {
    public static void main (String args [])
    {
        String hexValue = "00000156A56BE980";
        BigInteger result = new BigInteger(hexValue, 16);
        System.out.println(result);
    }
}

See also this repl.it

The problem is probably because your value does not fit within the value range (-2³¹ to 2³²-1) of Integer - see the docs

Answer 2

The number is too large for a 32-bit int

Try using a long instead.

public static void main(String[] args) {
    String hexValue = "00000156A56BE980";
    long result = Long.parseLong(hexValue, 16);
    System.out.println(result);
}

Note: you can't have spaces in a number. You can call .trim() to remove them.

Answer 3

2 thing in order the code can work:

1. remove spaces trimming the String
2. the result doenst fit in an integer so use either Long or BigInteger instead

 public static void main(String[] args) {
    String hexValue = " 00000156A56BE980 ";
    long result = Long.parseLong(hexValue.trim(), 16);
    System.out.println(result);
    }

Answer 4

The number is too big for integer (> 2^32).

(The value represented by the string is not a value of type int.)

Take a look here