UIApplicationLaunchOptionsShortcutItemKey not there in Swift 3?

Question

Recently in Xcode 8 beta 6 (8S201h), this has become a problem.

 UIApplicationLaunchOptionsShortcutItemKey

Here's the error :

Anyone else having this issue?

var performShortcutDelegate = true
if let shortcutItem = launchOptions[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
    print("ok")
    self.shortcutItem = shortcutItem
    performShortcutDelegate = false
}
return performShortcutDelegate

Try using `guard` : http://stackoverflow.com/questions/33689933/ambiguous-reference-to-member-subscript-on-dictionary — Bista, Aug 16 '16 at 05:20
So you're still getting the `ambiguous reference to member subscript` error? Your code looks correct as shown, so it might have something to do with the enclosing function. It's also possible you need to include the block `if #available(iOS 9.0, *) {}` around your shortcut code. More information/context would be helpful. :) — Naftali Beder, Aug 17 '16 at 14:40
So I just realized you're not unwrapping `launchOptions`, meaning it's still of `Optional` type when you try to use it. You can't pull values from an Optional dictionary, because it's [not technically a dictionary](http://stackoverflow.com/questions/24096293/assign-value-to-optional-dictionary-in-swift). That's likely the issue. I've updated my answer to reflect this, and included the enclosing function as well. Let me know if it works! — Naftali Beder, Aug 17 '16 at 14:48

Naftali Beder · Accepted Answer · 2016-08-24T12:50:55.013

7

The constant has changed (see the documentation). You also need to unwrap launchOptions before using any values it contains.

Enclosing function is included for context.

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    if let launchOptions = launchOptions {
        if #available(iOS 9.0, *) {
            if let shortcutItem = launchOptions[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
                print("Shortcut: \(shortcutItem)")
            }
        }
    }
    return true
}

edited Aug 24 '16 at 12:50

answered Aug 16 '16 at 17:58

Naftali Beder

1,066
1
10
27

1

If this is in [`application(_:willFinishLaunchingWithOptions:)`](https://developer.apple.com/reference/uikit/uiapplicationdelegate/1623032-application), then the `launchOptions` dictionary is already known to have key type `UIApplicationLaunchOptionsKey`. So you can just use `launchOptions[.shortcutItem]`. – rickster Aug 16 '16 at 18:37
Can you update your question to include the code and the function it's inside? (Ideally, please paste it as inline code, not as a screenshot.) – Naftali Beder Aug 16 '16 at 19:29
1

My problem was the migration tool who missed changing the `launchOptions` type. So basically check the `UIApplicationDelegate` for the correct method interface. Should be `launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil`. – ricardopereira Aug 26 '16 at 16:54

score 1 · Answer 2 · answered Sep 12 '16 at 11:44

The launchOptions Dictionary type has changed in the function parameters to [UIApplicationLaunchOptionsKey: AnyObject].

private func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: AnyObject]?) -> Bool {

    ...

}

score 0 · Answer 3 · answered Sep 22 '16 at 09:22

0

Try this.. Its work for me using Xcode8 , swift3

    //Check for ShortCutItem
    if #available(iOS 9.0, *) {
        if let shortcutItem = launchOptions?[UIApplicationLaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
        }
    }

answered Sep 22 '16 at 09:22

Chetan Dobariya

792
8
14

UIApplicationLaunchOptionsShortcutItemKey not there in Swift 3?

3 Answers3