Select text between brackets starting with ^{text to be selected} using regex

Question

Eg: sdadjaskdhas ^{sdassad ^{/frac{}{} s dcds &} dsdsadsa} ddsfsafdsfs

Answer should be: {sdassad ^{/frac{}{} s dcds &} dsdsadsa}

it should include any character between brackets

It is impossible to answer welll without knowing what programming language you are using for this task. — Wiktor Stribiżew, Aug 06 '16 at 09:28

Tejas Unnikrishnan · Accepted Answer · 2016-08-06T08:42:51.850

0

Use backspace to escape the ^,{,} characters as they belong to regex. .* to select any number of any characters.

Here is your answer: \^\{.*\}

EDIT: You can use this regex [^\^]\^{(\S)} , print the match, trim the string. Loop over this you find all matches in a string.

edited Aug 06 '16 at 08:42

answered Aug 06 '16 at 07:26

The brackets can also be of any type ^{}, ^[], ^(). Please help – Tarun Gupta Aug 06 '16 at 07:38
Not involving backslash in the output. "\f" is not coming if searched on "abc ^{\frac{}} dsad" – Tarun Gupta Aug 06 '16 at 07:45
Since the bracket can be of any type, you can blindly use .* to match any character. – Tejas Unnikrishnan Aug 06 '16 at 07:51
What should be output for `abc ^{\frac{}} dsad` ? `\frac{}` ? – Tejas Unnikrishnan Aug 06 '16 at 07:53
I want to match string between parentheses (starting should be ^{ ).e.g. 'abc ^{\frac{}} dsadabc ^{\frac{}} dsad' should match two times and should return ['\frac{}', '\frac{}'] – Tarun Gupta Aug 06 '16 at 08:14
You can use this regex `[^\^]*\^\{(\S*)\}` , print the match, trim the string. Loop over this you find all matches in a string. – Tejas Unnikrishnan Aug 06 '16 at 08:29
Thanks, This would do the job. – Tarun Gupta Aug 06 '16 at 08:40
You're welcome. I will edit the answer with this one and you can mark it as answer. – Tejas Unnikrishnan Aug 06 '16 at 08:42

1 Answers1