I need string that starts with number from my input string

Question

Here is my code

String itemName = "Daily 60k tube";
  String name="";
  if(itemName.matches(".*\\d+.*"))
        {
            itemName = itemName.substring(itemName.indexOf(" ") + 1);
            itemName = itemName.substring(0, itemName.indexOf(" "));
            name = itemName;
        }

I need that 60k as my name in the output. But it is crashing with exception. This is the exception.

java.lang.StringIndexOutOfBoundsException: length=6; regionStart=0; regionLength=-1
                                                                at java.lang.String.startEndAndLength(String.java:298)
                                                                at java.lang.String.substring(String.java:1087)

My output should be "60k". Please help me fixing this issue. Thanks in advance.

is it fixed you will get same kind of string? i mean "Daily 60k tube" type? — V-rund Puro-hit, Aug 03 '16 at 10:04
@vrund purohit I will get different values like "Daily cube only 50k" and output should be "50k" only. — , Aug 03 '16 at 10:06

Sanoop Surendran · Accepted Answer · 2016-08-03T10:23:35.463

1

You can try this

String itemName = "Daily 60k tube";
String name="";
if(itemName.matches(".*\\d+.*"))
{
    String[] array = itemName.split(" "); // Daily 60k tube
    // array: {"Daily","60k","tube"}
    for (String item : array) {
        if (item.matches(".*\\d+.*")) {
             name = item;
         }
    }
}

EDIT You can also replace the line with this

  (item.matches(".*\\d+.*" + "k")

So it will look like

    String[] array = itemName.split(" "); // Daily 60k tube
    // array: {"Daily","60k","tube"}
    for (String item : array) {
        if (item.matches(".*\\d+.*" + "k") {
             name = item;
         }
    }

Hope this helps

edited Aug 03 '16 at 10:23

answered Aug 03 '16 at 10:05

Sanoop Surendran

3,484
4
28
49

I will get different values like "Daily cube only 50k" and output should be "50k" only. – Aug 03 '16 at 10:12
this is working but I will get different strings wait.. I will update my question. – Aug 03 '16 at 10:22
Hope it helped..Thanks :): ) Happie coding @Android – Sanoop Surendran Aug 03 '16 at 10:32

score 1 · Answer 2 · answered Aug 03 '16 at 10:15

1

Try this piece of code

String Name;
String[] array = itemName.split(" ");
for (int i = 0; i < array.length;i++){
    if(Character.isDigit(array[i].charAt(0)))
    {
        Name = array[i];
        break;
    }

}

Hope this helps. Happy Coding :)

answered Aug 03 '16 at 10:15

Shrenik Shah

1,900
1
11
19

if you found it helpful to you and it resolves what you want kindly mark this as answer so that it can be useful to others as well. – Shrenik Shah Aug 03 '16 at 10:22

score 0 · Answer 3 · answered Aug 03 '16 at 10:11

0

I think this will helps you.

 int i=itemName.indexOf(" ") + 1;
    itemName = itemName.substring(i);
    i=itemName.indexOf(" ");
    itemName = itemName.substring(0,i);
    name = itemName;

answered Aug 03 '16 at 10:11

Shanto George

994
13
26

score 0 · Answer 4 · answered Aug 03 '16 at 10:20

Try this way:

private static String getResult(String itemName) {
        String[] result = itemName.split(" ");
        for (String i : result) {
            if (Character.isDigit(i.charAt(0))) {
                return i;
            }
        }
        return null;
    }

I need string that starts with number from my input string

4 Answers4