What does aveRP[0] == 0 and aveRP[0] > 0 in the code means?

Question

if(aveRP[0] == 0){}
else if(aveRP[0] > 0){
for(int i = 0 ; i < 100; i++){
double a = r.nextGaussian() * 0.3 + aveRP[0];
if (a < 0 || a > 1){}
else{ relinp.add(a);}

where aveRP is an array list of double variable type ?

We assume you know basic Java so it's not clear what you are asking. — Peter Lawrey, Aug 03 '16 at 08:34
@JFMeier , -difference between using = and == while referencing any element of an array list — Sarabjeet Singh, Aug 03 '16 at 08:46
@PeterLawrey i am learning java. This actually is not my code, so trying to understand the code and learning java — Sarabjeet Singh, Aug 03 '16 at 08:47
I suggest you read. https://docs.oracle.com/javase/tutorial/ it covers things like the difference between assignment `=` and a check for equality `==` — Peter Lawrey, Aug 03 '16 at 08:50
@PeterLawrey Thanks for the suggestion sir, I would go through it. — Sarabjeet Singh, Aug 03 '16 at 09:01

score 1 · Accepted Answer · answered Aug 03 '16 at 08:33

aveRP[0] == 0 This statement is checking whether the first element of array aveRP is 0 or not. If it is 0 then no code is executed. The else block again checks if it's greater than 0.

Bottomline, there are many un-necessary validations in your code. The code written in your question is equivalent to :

if(aveRP[0] > 0){
    for(int i = 0 ; i < 100; i++){
        double a = r.nextGaussian() * 0.3 + aveRP[0];
        if( !(a < 0 || a > 1) ){ relinp.add(a);}
    }
}

What does aveRP[0] == 0 and aveRP[0] > 0 in the code means?

1 Answers1