while loop read command is printing location rather than just file name- why is this?

Question

Can someone explain to me why when I print the $file_name variable in the below script, does it show the location and not just the file name? It's not necessarily a bad thing because I'm working towards trying to print the location, the md5sum and the file name separately, but I'm confused at this point why this is printing the location.

here is the text file:

day19-pgm-am_0946-23_p1_13.mov
day19-pgm-am_0951-23_p1_14.mov
day19-pgm-am_1016-23_p1_19.mov
day19-pgm-am_1021-23_p1_20.mov
day19-pgm-am_1111-23_p1_30.mov

.

#!/bin/bash


file=/location/md5sum.txt


while IFS=, read -ra arr; do
    while IFS= read -r -d '' file_name; do
        md5=($(md5sum "$file_name"))
        printf '%s\n' "$file_name $md5"
    done < <(find . -name "${arr[0]}" -print0)
done<"$file"

here is the current output, as you can see the data shows the files releative location:

./level1/level2/day19-pgm-am_0946-23_p1_13.mov d41d8cd98f00b204e9800998ecf8427e
./level1/day19-pgm-am_0946-23_p1_13.mov d41d8cd98f00b204e9800998ecf8427e
./level1/level2/day19-pgm-am_0951-23_p1_14.mov d41d8cd98f00b204e9800998ecf8427e
./level1/day19-pgm-am_0951-23_p1_14.mov d41d8cd98f00b204e9800998ecf8427e
./level1/level2/day19-pgm-am_1016-23_p1_19.mov d41d8cd98f00b204e9800998ecf8427e
./level1/day19-pgm-am_1016-23_p1_19.mov d41d8cd98f00b204e9800998ecf8427e
./level1/level2/day19-pgm-am_1021-23_p1_20.mov d41d8cd98f00b204e9800998ecf8427e
./level1/day19-pgm-am_1021-23_p1_20.mov d41d8cd98f00b204e9800998ecf8427e
./level1/level2/day19-pgm-am_1111-23_p1_30.mov d41d8cd98f00b204e9800998ecf8427e
./level1/day19-pgm-am_1111-23_p1_30.mov d41d8cd98f00b204e9800998ecf8427e

At least some contents of `csv` file and the output you got might be helpful in understanding your script. — Fazlin, Jul 27 '16 at 13:38
http://stackoverflow.com/questions/5456120/how-to-only-get-file-name-with-linux-find has ways to get only filenames.. but your find command has `print0` which might be a hurdle — Sundeep, Jul 27 '16 at 14:02

score 2 · Accepted Answer · answered Jul 27 '16 at 14:02

2

$file_name you're getting from find is the relative path to the file found by find from the directory supplied to find.

You can get the directory and the filename like this:

directory=`dirname $file_name`
just_filename=`basename $file_name`

And print these.

answered Jul 27 '16 at 14:02

MattH

37,273
11
82
84

Thanks I've just incorporated that in my script and its working nicely. – neilH Jul 27 '16 at 14:08

score 0 · Answer 2 · answered Jul 27 '16 at 14:05

Try this;

#!/bin/bash

file=/location/md5sum.txt


while IFS=, read -ra arr; do
    while IFS= read -r -d '' file_name; do
        md5=($(md5sum "$file_name"))
        printf '%s\n' "$(basename $file_name) $md5"
    done < <(find . -name "${arr[0]}" -print0)
done<"$file"

score 0 · Answer 3 · answered Jul 27 '16 at 14:10

0

You can also use string operators:

printf '%s\n' "${file_name##*/} $md5"

This will cut everything till the last /

answered Jul 27 '16 at 14:10

Fazlin

2,285
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29

while loop read command is printing location rather than just file name- why is this?

3 Answers3