Handle number in string php (Part2)

Question

this is my problem 1 here: Handle number in string PHP . I solved it.

Now, i see new problem, you can see the picture:

I want to get only number, not date (500000 and 200000) and sum it.

This is my code without date:

$total= 0;
    $ex = explode(' ',$_POST['txtSalary']);
    function total($ex) {
        global $total;
        return $total+=$ex;
    }
    array_map('total',$ex);
    echo $total."<br/>";

I try so much but no result, hope you can help me. Thank you!

show the actual content of `$_POST['txtSalary']` by printing it out. `print_r($_POST['txtSalary']);` show the value — Alive to die - Anant, Jul 27 '16 at 10:02
`var_dum($ex)` and see what you are getting. You are not getting proper values from `explode`. — Sougata Bose, Jul 27 '16 at 10:03
`$ex` is an array. Problem: you are trying to add array to integer — rokas, Jul 27 '16 at 10:05
Does $_POST['txtSalary'] an array? 'Cause you can't explode an array. And why are you using array_map if u only need second part of explode? Use instead $total += $ex[1]; — Mehmet SÖĞÜNMEZ, Jul 27 '16 at 10:08
Please check this link:- https://eval.in/612692 .. If is it correct, let me know. i will post it as an answer. thanks — Alive to die - Anant, Jul 27 '16 at 10:10

score 1 · Accepted Answer · answered Jul 28 '16 at 04:23

I assume that your $_POST['txtSalary'] look like below:-

$_POST['txtSalary'] = '-27/07/2016: 5000000
-01/08/2016: 2000000';

So do like below:-

<?php

$_POST['txtSalary'] = '-27/07/2016: 5000000
-01/08/2016: 2000000';

$array = explode(PHP_EOL, $_POST['txtSalary']);
print_r($array);

$sum = 0;
foreach($array as $arr){
   $sum += explode(': ',$arr)[1];
}

echo $sum;

Output:- https://eval.in/612692

Handle number in string php (Part2)

1 Answers1