convert timestamp string to timestamp integer php

Question

Here is my php code

var_dump($args['startdate']); 
var_dump((int)$args['startdate']);die();

Here is output

string(13) "1468821556126" int(2147483647)

Expected output

string(13) "1468821556126" int(1468821556126)

Why this is happening and how to resolve this issue ?

What's the issue? What does *"resolve"* mean in this context? — BeetleJuice, Jul 23 '16 at 06:30
`int idate ( string $format [, int $timestamp = time() ] )` read more at http://php.net/manual/en/function.idate.php — , Jul 23 '16 at 06:32
@PraveenKumar thanks. I understand now. I've written an answer — BeetleJuice, Jul 23 '16 at 06:38

BeetleJuice · Accepted Answer · 2016-07-23T06:48:17.573

2

You cannot get a reliable result because your number is too large to be represented as an integer.

echo PHP_INT_MAX; //2147483647 on my system

For a number as large as yours, if you need it in numerical format, cast it to a float instead of an integer

echo floatval('1468821556126'); //1.46882155613E+12

From there, if you're trying to get a date, I assume that this is Javascript time, which is in milliseconds. To convert to a Unix Timestamp, you'll then need to divide it by 1000.

edited Jul 23 '16 at 06:48

answered Jul 23 '16 at 06:35

BeetleJuice

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It is working.. thanks for the answer... :) – Praveen Kumar Jul 23 '16 at 06:40

adarshdec23 · Answer 2 · 2016-07-23T06:43:05.943

1

You're probably using a 32bit system. The number you're seeing is the maximum size of an int on a 32 bit machine. Use float or change to a 64bit machine.

Ref: PHP Integer

edited Jul 23 '16 at 06:43

answered Jul 23 '16 at 06:34

adarshdec23

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How can i get desired output ?? i know what you are saying already... :) – Praveen Kumar Jul 23 '16 at 06:37
Could you provide a little more context as to why you need integer? PHP is very flexible when it comes to data type. More often than not, you don't have to worry about it. – adarshdec23 Jul 23 '16 at 06:39
@PraveenKumar you cannot get exactly `int(1468821556126)` from a `var_dump` because PHP integers don't go that high. Cast to a float instead as I do in my solution (or as is suggested on this one) – BeetleJuice Jul 23 '16 at 06:39
@adarshdec23 i just want date from it... – Praveen Kumar Jul 23 '16 at 06:40
@adarshdec23 `echo date("Y-m-d",strtotime($args['startdate']));` output was `1970-01-01`.... ;) – Praveen Kumar Jul 23 '16 at 06:45

score 1 · Answer 3 · answered Jul 23 '16 at 06:36

1

It's happening because your $args['startdate'] is in miliseconds, you need to divide it by 1000

answered Jul 23 '16 at 06:36

lulco

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If `$args['startdate']` is a timestamp then this is the only correct answer. `echo(date("Y-m-d H:i:s e", 1468821556126/1000));` prints `2016-07-18 08:59:16 Europe/Bucharest`. – axiac Jul 23 '16 at 06:47
@axiac This is probably what the op is looking for. – adarshdec23 Jul 23 '16 at 06:49

convert timestamp string to timestamp integer php

3 Answers3