I am learning common lisp.
It's not explained anywhere but I tried:
(eq '(a b c) '(a b c))
which evaluates to NIL.
Why returning Nil from lisp's perspective? I am interested to know how it evaluates to Nil in this case.
Thank you.
I am learning common lisp.
It's not explained anywhere but I tried:
(eq '(a b c) '(a b c))
which evaluates to NIL.
Why returning Nil from lisp's perspective? I am interested to know how it evaluates to Nil in this case.
Thank you.