regex to match everything except protocol from url

Question

I have the following regex pattern: (?:http.?:\/\/)

This matches the protocol component from a web url, I want a regex to do the opposit, to match everything except the protocol, so far my every attempt has not worked at all.

Becuase ultimatly what I want to do is check if two urls are the same reguardless of protocol, so I can do:

if url_1[regex] == url_2[regex]

Chris Lear · Accepted Answer · 2016-07-08T11:33:49.463

2

This should do it:

/.*?\/\/(.*)/

edited Jul 08 '16 at 11:33

answered Jul 08 '16 at 11:25

Chris Lear

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Is there any way to do this without a capture group? `(?!.*\/\/).*` almost works, but it still matchs the last `/`, ok, doing this: `(?!.*\/\/)\w.*` works, problem soved. – Thermatix Jul 08 '16 at 12:25

anubhava · Answer 2 · 2016-07-08T11:31:45.010

0

You can use this regex to always capture the part after optional http:// or https:// at the start:

/^(?:[^:]+:\/\/)?(.+)$/

RegEx Demo

edited Jul 08 '16 at 11:31

answered Jul 08 '16 at 11:29

anubhava

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score 0 · Answer 3 · answered Jul 08 '16 at 11:59

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Use this and take the second group $2

/^(?:[^:]*:\/\/)?(.*?)$/

answered Jul 08 '16 at 11:59

Wilmer

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regex to match everything except protocol from url

3 Answers3