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I am build html5 android app using crosswalk. When i do build android it outputs two separate APK files, one for armv7 and one for x86. i just want one form armv7 only but always result bot architectures even if i put target param in command. i did these commands but still make 2 files:

  • crosswalk-pkg t="arm" path
  • crosswalk-pkg t=arm path
  • crosswalk-pkg t="a" path
  • crosswalk-pkg target="arm" path

what is actually right command to build armv7 only?

A Softle Gundam
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1 Answers1

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You have to precede options with minus signs.
One if you use the shortcut (-t) or two if you use the entire name (--targets).

crosswalk-pkg -t="armeabi-v7a" path #builds only v7a
crosswalk-pkg -t="arm" path #builds both arm v7a & v8a
crosswalk-pkg --targets="32" ./ #<default> builds both arm & x86 for 32bits
Ivan Ferrer Villa
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