What is the Maximum value for Java Duration

Question

I tried to create a max Duration in Java 8 by using Duration.ofMillis(Long.MAX_VALUE) but got a long overflow. How would I programmatically get the equivalent of a Duration.MAX_VALUE if it existed?

Edit: The long overflow was likely caused by an attempt to add to the value instead of during construction. Apologies for not having reproducible code.

score 14 · Accepted Answer · answered Mar 05 '20 at 16:14

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Simple:

Duration maxDur = ChronoUnit.FOREVER.getDuration();

answered Mar 05 '20 at 16:14

Nick J. R. T.

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Wow, no idea this existed, definitely what I was looking for way back when – Novaterata Mar 05 '20 at 16:23
which is defined as `FOREVER("Forever", Duration.ofSeconds(Long.MAX_VALUE, 999_999_999))` and documented as "... The estimated duration of this unit is artificially defined as the **largest duration supported by Duration**." – user85421 Mar 05 '20 at 16:25

Alexey · Answer 2 · 2016-07-06T17:02:45.707

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It looks like Duration is stored in seconds (up to Long.MAX_VALUE) and nanoseconds (up to 999,999,999). Then the biggest duration possible is:

Duration d = Duration.ofSeconds(Long.MAX_VALUE, 999_999_999);

When I print it (System.out.print(d)) I get the following:

PT2562047788015215H30M7.999999999S

which means: 2562047788015215 hours, 30 minutes, and 7.999999999 seconds.

edited Jul 06 '16 at 17:02

answered Jul 06 '16 at 16:07

Alexey

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seconds can be negative so it should be `Long.MIN_VALUE..LONG.MAX_VALUE` – jhamon Jul 06 '16 at 16:30
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That duration is equivalent to around 292 billion years. – Tuupertunut Aug 19 '17 at 02:03
While this does produce the highest java.time.Duration, java.time already provides this with `ChronoUnit.FOREVER`. See my [succinct answer](https://stackoverflow.com/a/60549713/2812695). – Nick J. R. T. Mar 05 '20 at 16:19

score 8 · Answer 3 · edited Jun 20 '20 at 09:12

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According to the Javadoc:

The duration uses nanosecond resolution with a maximum value of the seconds that can be held in a long.

The range of a duration requires the storage of a number larger than a long. To achieve this, the class stores a long representing seconds and an int representing nanosecond-of-second, which will always be between 0 and 999,999,999. The model is of a directed duration, meaning that the duration may be negative.

edited Jun 20 '20 at 09:12

Community

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answered Jul 06 '16 at 15:37

jhamon

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So why would Long.MAX_VALUE cause an overflow? What is the maximum value allowed for the Seconds portion? – Novaterata Jul 06 '16 at 15:39
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well, I just tried this piece of code: `Duration test = Duration.ofMillis(Long.MAX_VALUE);`and I don't get an overflow. Could you show the code that throws the exception? – jhamon Jul 06 '16 at 15:48
I no longer have it sorry. You know, it must have been caused later when something was added to it. – Novaterata Jul 06 '16 at 17:12

What is the Maximum value for Java Duration

3 Answers3