Instagram api error bad request ios

Question

Hi I am having an issue with Instagram while performing authentication process. It was working fine few weeks ago, nothing changed in the code.

The issue now facing is that after a login process of Instagram, safari display an error "Bad request 400" and nothing more then that.

Are you passing access token in your request ? – Saurabh Chaturvedi Jul 03 '16 at 07:25 — Saurabh Chaturvedi, Jul 03 '16 at 07:25

score 4 · Answer 1 · answered Jun 24 '16 at 10:41

4

Recently I had the same problem with the Instagram api. Everything was working fine and suddenly 400 bad request - You must provide a client_id.

I debugged the OAuth 2.0 flow and after extensive research realized that I should set a

Content-Type:application/x-www-form-urlencoded

header in the request. So if someone else has this problem make sure you have the header set in the request that retrieves the access token.

answered Jun 24 '16 at 10:41

iliyan tanev

377
2
15

Before you made this change, was the OAuth working for you sporadically? – shakked Jun 24 '16 at 21:39
Also, can anyone confirm that this solves their problems? – shakked Jun 24 '16 at 21:47
this didn't help. My app had been working fine for almost a year now and now randomly it stopped working completely – sudoExclaimationExclaimation Jun 26 '16 at 07:13
@shakked No, everything was fine until recently. I 'm using InstaSharp library for making my calls to Instagram and I have caught the error though fiddler. – iliyan tanev Jun 26 '16 at 18:51
@iliyantanev check out my response here with solution: http://stackoverflow.com/a/38037520/1634905 – sudoExclaimationExclaimation Jun 27 '16 at 00:09
@PranoyC wow, thank you for the insight. I hope Instagram resolves this soon – shakked Jun 27 '16 at 00:20
@shakked this resolved my issue. For anyone wondering, I'm on a .NET using `WebClient.UploadString` and explicitly set the method to `POST` – DPac Jul 14 '16 at 21:20

score 1 · Answer 2 · edited Oct 08 '19 at 17:05

I used WKWEbView because of redirect uri

func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
        //print(webView.url?.absoluteString)
        decisionHandler(.allow)

        let searchString = "https://example.com"//your redirect uri


        if (webView.url?.absoluteString.starts(with: searchString))! {
            let code = extractCode(webView.url!.absoluteString)
              if code != nil{
                print("*****found")
                  print("code: \(code)")
                  self.loginWithInstagram(code!)
              }
          }
    }


    func loginWithInstagram(_ code: String) {

        let headers = [
          "Content-Type": "application/x-www-form-urlencoded",
          "Accept": "*/*",
          "Cache-Control": "no-cache",
          "Host": "api.instagram.com",
          "Accept-Encoding": "gzip, deflate",
          "Content-Length": "237",
          "Connection": "keep-alive",
          "cache-control": "no-cache"
        ]

        let postData = NSMutableData(data: "client_id=xxx".data(using: String.Encoding.utf8)!)
        postData.append("&code=".data(using: String.Encoding.utf8)!)
        postData.append(code.data(using: String.Encoding.utf8)!)
        postData.append("&redirect_uri=https://example.com".data(using: String.Encoding.utf8)!)
        postData.append("&grant_type=authorization_code".data(using: String.Encoding.utf8)!)
        postData.append("&client_secret=xxx".data(using: String.Encoding.utf8)!)

        let request = NSMutableURLRequest(url: NSURL(string: "https://api.instagram.com/oauth/access_token")! as URL,
                                                cachePolicy: .useProtocolCachePolicy,
                                            timeoutInterval: 10.0)
        request.httpMethod = "POST"
        request.allHTTPHeaderFields = headers
        request.httpBody = postData as Data

        let session = URLSession.shared
        let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in


            guard let unwrappedData = data else { return }
            do {
                let str = try JSONSerialization.jsonObject(with: unwrappedData, options: .allowFragments)

                print(str)

            } catch {
                print("json error: \(error)")
            }

          if (error != nil) {
            //print(error)
          } else {
            let httpResponse = response as? HTTPURLResponse
            //print(httpResponse)
          }
        })

        dataTask.resume()
    }
}

// This works on my app

score 0 · Answer 3 · answered Jun 29 '16 at 03:57

0

The problem you're seeing is related to the callback URL. Instagram no longer seems to accept custom schemes. Your callback needs to be http or https ( it can't be, for example customapp:// ).

answered Jun 29 '16 at 03:57

Alex

712
1
5
11

How would you do authentication on an iOS app then? – shakked Jun 29 '16 at 04:16
You need to do in a web view ( UI or WK ). Intercept the relevant delegate methods. In the case of UIWebView, check for your callback URL when the delegate is asked if it should load a URL. If it's your callback URL, return NO to stop the loading, parse the token out of the URL and you're on your way. – Alex Jun 29 '16 at 04:20

Instagram api error bad request ios

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