How to catch integers in dictionary keys, most of them string, but some is integers that I need to remove

Question

How to catch integers in dictionary keys, most of them string, but some is integers that i need to remove.

I tried this:

def print_words(filename):
    dict = create_dict(filename)
    for key, val in sorted(dict.items()):

        # Integer filter here! 
        # if not isinstance(dict.key, int)     Something wrong here!

        print '{1:^5}\t{0:<}'.format(key.encode('utf-8'), val)
    return

if not isinstance(key, int) # thanks, but integers still pass... maybe it's not an integer?! — Paul Silber, Jun 20 '16 at 08:28
it is give nothing. My key is words, value of key is just counter... — Paul Silber, Jun 20 '16 at 08:37

Maroun · Accepted Answer · 2016-06-20T08:33:16.043

0

You already have key and val in your loop, dict.key is wrong.

You can use this instead:

{k:v for k, v in d.items() if not isinstance(k, int)}

Or, just replace the line that doesn't work for you with:

if not isinstance(key, int):
    # key is not integer

edited Jun 20 '16 at 08:33

answered Jun 20 '16 at 08:27

Maroun

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`{k:v for k, v in d.iteritems() if NOT isinstance(k, int)}` – Julien Goupy Jun 20 '16 at 08:30
I still have numbers instead words, from left its value, from the right it's key. here below an example. 1 84-85 5 9 35 a 1 adder 1 addition 5 adventures – Paul Silber Jun 20 '16 at 10:52

How to catch integers in dictionary keys, most of them string, but some is integers that I need to remove

1 Answers1