Normally, if you know all the types you intend to create before hand, you can just do something like this:
typedef enum{
BASE_CREATURE_TYPE = 0,
ANIMAL_CREATURE_TYPE,
...
}CREATURE_TYPES
But this becomes tedious, because each time you create a new class, you need to update the enum. Also, the CREATURE_TYPES is still just items in an enum - how to tie to an actual class ?
I was wondering if there was some way, I could just write the classes, and at run time, without actually instantiating an object, create a set containing all the types.
Is this possible in C++? In Java there is something called "static blocks", which are executed when the class is loaded by the JVM.
EDIT: This question is not about static blocks - It is just an example - I am wondering if there is some way, that I can execute a method or block of code so I know what classes exist at runtime, without actually creating an object
EDIT: I meant set of all types, not "maps", so I can create an object of each type, without having to maintain a list.
EDIT: The reason I want this, is because I am trying to create a function that can call methods on all derived classes that are part of the application. For example, say I have several classes which all derive from class Foo, and have a balls():
Foo{
balls();
}
Boo : public Foo{
balls();
}
Coo: public Foo{
balls():
}
At run time, I would like to know about all the derived classes so I can call:
DerivedClass:balls();
EDIT: Note, that I do not need to know about all the members of each derived class, I just want to know what all the derived classes are, so I can call balls(), on each of them.
EDIT: This question is similar: How to automatically register a class on creation
But unfortunately, he is storing an std::string(). How does one refer to the actual class ?
EDIT: In Smeehey's answer below, in the main method, how would I actually create an instance of each class, and call both static and non-static methods ?