I want to find out users who are not deleted and not disabled. I know I can use two search criteria and use them together there by creating one more search criteria. But as the NOT_IN and IN operators are given I wanted to know how I can use that functionality?
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Another way to do this is to do two seperate Search Criteria and then combine them in one.
UserManager userManager = Platform.getService(UserManager.class);
SearchCriteria criteria1 = new SearchCriteria(UserManagerConstants.AttributeName.STATUS.getId(), UserManagerConstants.AttributeValues.USER_STATUS_DELETED.getId(), SearchCriteria.Operator.NOT_EQUAL);
SearchCriteria criteria2 = new SearchCriteria(UserManagerConstants.AttributeName.STATUS.getId(), UserManagerConstants.AttributeValues.USER_STATUS_DISABLED.getId(), SearchCriteria.Operator.NOT_EQUAL);
SearchCriteria combined = new SearchCriteria(criteria1, criteria2, SearchCriteria.Operator.AND);
HashMap<String,Object> configParams = new HashMap<String,Object>();
configParams.put("ENDROW", -1);
List<User> results = userManager.search(combined, null, configParams);

Ioanna Katsanou
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you can use the OIM search criteria as follows:
UserManager usrMgr = oimClient.getService(UserManager.class);
List<String> listOfStatus = new ArrayList<String>();
listOfStatus.add("Disabled");
listOfStatus.add("Deleted");
SearchCriteria statusSearchCriteria = new SearchCriteria(UserManagerConstants.AttributeName.STATUS.getId(), listOfStatus, SearchCriteria.Operator.NOT_IN);
try {
List<User> retList = usrMgr.search(statusSearchCriteria, null, null);
System.out.println(retList.toString());
} catch (Exception e) {
e.printStackTrace();
}

Kunal Varpe
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1i believe this answer is incorrect, as the documentation for the search method of UserManager states that "The SearchCriteria Operators supported are AND, OR, NOT, GREATER_THAN, GREATER_EQUAL, LESS_THAN, LESS_EQUAL, EQUAL and NOT_EQUAL. For additional comparisons like contains the SearchCriteria Operator will be EQUAL with value to be searched will be '*
*' " The other answer seems like the correct solution – Alvin Baena Apr 06 '17 at 15:48